Equations of Lines — Question 3

PDF ↗

Question 3

Points A=(1,−2,3),B=(5,4,−1),P=(4,u,v)A=(1,-2,3),\qquad B=(5,4,-1),\qquad P=(4,u,v) are collinear, and PP lies between AA and BB.

Tasks

  1. Determine uu and vv.

  2. Write a parametric equation of the common line.

  3. Find the ratio AP:PBAP:PB and verify it using distances.

Original worksheet page 1: question and worked solution for 1-2-003
Show solutionHide solution

Question 3 – Solution

Strategy Parameterize the segment from AA to BB. The known xx-coordinate of PP determines the parameter, after which the other coordinates and division ratio follow.

See the diagram in the original worksheet below.

Parameter and coordinates Since B−A=⟨4,6,−4⟩B-A=\left\langle 4,6,-4\right\rangle, r→(t)=⟨1,−2,3⟩+t⟨4,6,−4⟩.\vec r(t)=\left\langle 1,-2,3\right\rangle+t\left\langle 4,6,-4\right\rangle. At PP, 1+4t=41+4t=4, so t=3/4t=3/4. Therefore u=−2+6(34)=52,v=3−4(34)=0,u=-2+6\left(\tfrac 34\right)=\tfrac 52,\qquad v=3-4\left(\tfrac 34\right)=0, and P=(4,52,0).\boxed{P=\left(4,\tfrac 52,0\right)}.

Division ratio The parameter places PP three-fourths of the way from AA to BB, so AP:PB=3:1.\boxed{AP:PB=3:1}.

Verification We have P−A=34(B−A)P-A=\tfrac 34(B-A) and B−P=14(B−A)B-P=\tfrac 14(B-A); taking lengths preserves the ratio 3:13:1.

Original worksheet page 2: question and worked solution for 1-2-003

Original worksheet layout. Use Enlarge or open the PDF for a closer view.