Triple Integrals — Question 7

PDF ↗

Question 7

For E={x,y,z≥0:x+y+z≤1}E=\{x,y,z\ge 0:x+y+z\le 1\}, rewrite ∭EzdV\iiint_E z\,dV in the orders dzdydxdz\,dy\,dx and dxdzdydx\,dz\,dy, then evaluate.

Tasks

  1. Give both sets of bounds.

  2. Evaluate one order.

  3. Verify by symmetry.

Original worksheet page 1: question and worked solution for 4-5-007
Show solutionHide solution

Question 7 – Solution

Strategy. Each order peels coordinates from the simplex inequality.

Step 1: GeometryThe simplex is bounded by the coordinate planes and x+y+z=1x+y+z=1. The two marked fibers show which coordinate is peeled off first.

See the diagram in the original worksheet below.

Step 2: OrdersI=∫01∫01−x∫01−x−yzdzdydx=∫01∫01−y∫01−y−zzdxdzdyI=\int_0^1\int_0^{1-x}\int_0^{1-x-y}z\,dz\,dy\,dx=\int_0^1\int_0^{1-y}\int_0^{1-y-z}z\,dx\,dz\,dy. The first form gives I=16∫01(1−x)3dx=124I=\frac 16\int_0^1(1-x)^3dx=\boxed{\frac 1{24}}.

VerificationThe simplex volume is 1/61/6 and its centroid has z‾=1/4\bar z=1/4, so the moment is (1/6)(1/4)=1/24(1/6)(1/4)=1/24.

Original worksheet page 2: question and worked solution for 4-5-007

Original worksheet layout. Use Enlarge or open the PDF for a closer view.