Higher Order Partial Derivatives — Question 7

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Question 7

For w(x,y,z)=x2yz3+sin⁡(xz)w(x,y,z)=x^2yz^3+\sin(xz):

Tasks

  1. Find wxyzw_{xyz}.

  2. Find wzzxw_{zzx}.

  3. Evaluate both at (1,2,0)(1,2,0) and discuss derivative order.

Original worksheet page 1: question and worked solution for 2-4-007
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Question 7 – Solution

Strategy. Follow the subscripts and keep polynomial and trigonometric contributions separate.

Step 1: wxyzw_{xyz} wx=2xyz3+zcos⁡(xz),wxy=2xz3,wxyz=6xz2.w_x=2xyz^3+z\cos(xz),\quad w_{xy}=2xz^3,\quad \boxed{w_{xyz}=6xz^2}.

Step 2: wzzxw_{zzx} wz=3x2yz2+xcos⁡(xz),w_z=3x^2yz^2+x\cos(xz), wzz=6x2yz−x2sin⁡(xz),w_{zz}=6x^2yz-x^2\sin(xz), wzzx=12xyz−2xsin⁡(xz)−x2zcos⁡(xz).\boxed{w_{zzx}=12xyz-2x\sin(xz)-x^2z\cos(xz)}.

Step 3: Evaluate Both happen to equal 0\boxed 0 at (1,2,0)(1,2,0). Smoothness permits reordering derivatives that contain the same multiset of variables; xyzxyz and zzxzzx are different derivative types and need not agree generally.

Original worksheet page 2: question and worked solution for 2-4-007

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