Higher Order Partial Derivatives — Question 1

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Question 1

For f(x,y)=x4y2−3x2y3+2xy,f(x,y)=x^4y^2-3x^2y^3+2xy, Tasks

  1. Find fxx,fxy,fyx,fyyf_{xx},f_{xy},f_{yx},f_{yy}.

  2. Evaluate them at (1,−1)(1,-1).

  3. Verify the mixed-partial equality algebraically.

Original worksheet page 1: question and worked solution for 2-4-001
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Question 1 – Solution

Strategy. Compute both first partials before differentiating again.

Step 1: First partials fx=4x3y2−6xy3+2y,fy=2x4y−9x2y2+2x.f_x=4x^3y^2-6xy^3+2y,\qquad f_y=2x^4y-9x^2y^2+2x.

Step 2: Second partials fxx=12x2y2−6y3,fxy=8x3y−18xy2+2,\boxed{f_{xx}=12x^2y^2-6y^3},\qquad \boxed{f_{xy}=8x^3y-18xy^2+2}, fyx=8x3y−18xy2+2,fyy=2x4−18x2y.\boxed{f_{yx}=8x^3y-18xy^2+2},\qquad \boxed{f_{yy}=2x^4-18x^2y}.

Step 3: Evaluate fxx(1,−1)=18,fxy(1,−1)=fyx(1,−1)=−24,fyy(1,−1)=20.\boxed{f_{xx}(1,-1)=18},\quad \boxed{f_{xy}(1,-1)=f_{yx}(1,-1)=-24},\quad \boxed{f_{yy}(1,-1)=20}. The two mixed formulas coincide term by term, as expected for a polynomial.

Original worksheet page 2: question and worked solution for 2-4-001

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