Barrier Tunneling — Question 3

Section 38-8 · Physics pages 6396–6397

Question 3 A thickness change can be inferred from a transmission ratio Two otherwise identical opaque barriers have widths a and a + ∆a, with ∆a > 0. Their decay constant is κ = 8.00 nm−1. Use T(a) ≃Ce−2κa with the same width-independent prefactor C. Transmission decreases by a factor of 100. x ∆a Schematic; labels, not drawing lengths, specify the data. (a) Derive the relation between the transmission ratio and ∆a. (b) Find the added width and the logarithmic sensitivity to thickness.
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Question 3 - Solution A thickness change can be inferred from a transmission ratio x ∆a (a) Method and calculation T(a + ∆a) T(a) = e−2κ∆a = 1/100. ∆a = ln 100 2κ = .287823 nm . (b) Interpretation and further calculation ln T = ln C −2κa ⇒ d ln T da = −2κ = −16.0 nm−1 . δT/T ≃−2κ δa (|2κδa| ≪1). Physical check The ratio removes the unknown common prefactor. The differential formula is for small changes and must not replace the logarithm for a hundredfold change.

Question 3

A thickness change can be inferred from a transmission ratio

Two otherwise identical opaque barriers have widths a and a+Δaa+\Delta a, with Δa>0\Delta a>0. Their decay constant is κ=8.00nm−1\kappa=8.00\,\mathrm{nm}^{-1}. Use T(a)≃Ce−2κaT(a)\simeq Ce^{-2\kappa a} with the same width-independent prefactor C. Transmission decreases by a factor of 100.

Diagram shown in the original SVG worksheet.

  1. Derive the relation between the transmission ratio and Δa\Delta a.

  2. Find the added width and the logarithmic sensitivity to thickness.

Question 3 - Solution

A thickness change can be inferred from a transmission ratio

Diagram shown in the original SVG worksheet.

(a) Method and calculation

T(a+Δa)T(a)=e−2κΔa=1/100.\frac{T(a+\Delta a)}{T(a)}=e^{-2\kappa\Delta a}=1/100.Δa=ln⁡1002κ=.287823nm.\boxed{\Delta a=\frac{\ln100}{2\kappa}=.287823\,\mathrm{nm}}.

(b) Interpretation and further calculation

ln⁡T=ln⁡C−2κa⇒dln⁡Tda=−2κ=−16.0nm−1.\ln T=\ln C-2\kappa a\quad\Rightarrow\quad\boxed{\frac{d\ln T}{da}=-2\kappa=-16.0\,\mathrm{nm}^{-1}}.δT/T≃−2κδa(|2κδa|≪1).\boxed{\delta T/T\simeq-2\kappa\,\delta a}\qquad(|2\kappa\delta a|\ll1).

Physical check

The ratio removes the unknown common prefactor. The differential formula is for small changes and must not replace the logarithm for a hundredfold change.