Barrier Tunneling — Question 2

Section 38-8 · Physics pages 6394–6395

Question 2 The opaque-barrier approximation has a quantifiable relative error For a rectangular barrier at E = V0/2, the exact formula reduces to T = [1 + sinh2 z]−1, with z = κa > 0. z T dashed: opaque Schematic; labels, not drawing lengths, specify the data. (a) Rewrite T in exponentials and derive its leading approximation at large z. (b) Find the relative overestimate of that approximation at z = 3.
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Question 2 - Solution The opaque-barrier approximation has a quantifiable relative error z T dashed: opaque (a) Method and calculation T = sech2 z = 4e−2z (1 + e−2z)2 . z ≫1 : Top = 4e−2z . (b) Interpretation and further calculation Top −T T = 2e−2z + e−4z . z = 3 : T = .00986604, Top = .00991501, relative error = .00496365 . Physical check The exponential alone omits a boundary prefactor of four in this special case. The leading opaque expression can exceed one if used outside its valid regime.

Question 2

The opaque-barrier approximation has a quantifiable relative error

For a rectangular barrier at E=V0/2E=V_0/2, the exact formula reduces to T=[1+sinh⁡2z]−1T=[1+\sinh^2z]^{-1}, with z=κa>0z=\kappa a>0.

Diagram shown in the original SVG worksheet.

  1. Rewrite T in exponentials and derive its leading approximation at large z.

  2. Find the relative overestimate of that approximation at z=3z=3.

Question 2 - Solution

The opaque-barrier approximation has a quantifiable relative error

Diagram shown in the original SVG worksheet.

(a) Method and calculation

T=sech⁡2z=4e−2z(1+e−2z)2.T=\operatorname{sech}^2z=\frac{4e^{-2z}}{(1+e^{-2z})^2}.z≫1:Top=4e−2z.z\gg1:\quad\boxed{T_{\mathrm{op}}=4e^{-2z}}.

(b) Interpretation and further calculation

Top−TT=2e−2z+e−4z.\boxed{\frac{T_{\mathrm{op}}-T}{T}=2e^{-2z}+e^{-4z}}.z=3:T=.00986604,Top=.00991501,relative error=.00496365.z=3:\quad\boxed{T=.00986604,\quad T_{\mathrm{op}}=.00991501,\quad\text{relative error}=.00496365}.

Physical check

The exponential alone omits a boundary prefactor of four in this special case. The leading opaque expression can exceed one if used outside its valid regime.