Barrier Tunneling — Question 4

Section 38-8 · Physics pages 6398–6399

Question 4 Mass changes tunneling exponentially even at the same incident kinetic energy Two species have masses m and 2m. They encounter the same rectangular barrier with the same energy 0 < E < V0 and width a. Both are in the opaque regime. The lighter species has κma = 4.00. Use T ≃[16E(V0 −E)/V 2 0 ]e−2κa. x |ψ| m 2m Schematic; labels, not drawing lengths, specify the data. (a) Derive the ratio of decay constants and transmissions. (b) Calculate T2m/Tm and the inverse enhancement factor.
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Question 4 - Solution Mass changes tunneling exponentially even at the same incident kinetic energy x |ψ| m 2m (a) Method and calculation κ = √ 2m(V0 −E)/ℏ ⇒ κ2m = √ 2 κm . T2m Tm ≃exp[−2κma( √ 2 −1)] . (b) Interpretation and further calculation T2m/Tm = e−8( √ 2−1) = .0363810 . Tm/T2m = 27.4869 . Physical check At fixed energy and barrier height the prefactor is mass-independent in this approximation. The strong mass dependence comes from the exponential action.

Question 4

Mass changes tunneling exponentially even at the same incident kinetic energy

Two species have masses m and 2m2m. They encounter the same rectangular barrier with the same energy 0<E<V00<E<V_0 and width a. Both are in the opaque regime. The lighter species has κma=4.00\kappa_m a=4.00. Use T≃[16E(V0−E)/V02]e−2κaT\simeq[16E(V_0-E)/V_0^2]e^{-2\kappa a}.

Diagram shown in the original SVG worksheet.

  1. Derive the ratio of decay constants and transmissions.

  2. Calculate T2m/TmT_{2m}/T_m and the inverse enhancement factor.

Question 4 - Solution

Mass changes tunneling exponentially even at the same incident kinetic energy

Diagram shown in the original SVG worksheet.

(a) Method and calculation

κ=2m(V0−E)/ℏ⇒κ2m=2κm.\kappa=\sqrt{2m(V_0-E)}/\hbar\quad\Rightarrow\quad\boxed{\kappa_{2m}=\sqrt2\,\kappa_m}.T2mTm≃exp⁡[−2κma(2−1)].\boxed{\frac{T_{2m}}{T_m}\simeq\exp[-2\kappa_m a(\sqrt2-1)]}.

(b) Interpretation and further calculation

T2m/Tm=e−8(2−1)=.0363810.\boxed{T_{2m}/T_m=e^{-8(\sqrt2-1)}=.0363810}.Tm/T2m=27.4869.\boxed{T_m/T_{2m}=27.4869}.

Physical check

At fixed energy and barrier height the prefactor is mass-independent in this approximation. The strong mass dependence comes from the exponential action.