Gauss' Law for Magnetic Fields — Question 7

Section 32-1 · Physics pages 5184–5185

Question 7 A radial inverse-square field passes a local test but fails a global magnetic test For r greater than zero, a proposed field is B = Kˆr/r2. Assume it is intended to describe an ordinary magnetic field in all space, with no magnetic monopoles. proposed radial field Schematic; labels, not drawing lengths, specify the data. (a) Compute its divergence away from the origin and its flux through a sphere. (b) Determine what K must be if every closed surface must have zero magnetic flux.
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Question 7 - Solution A radial inverse-square field passes a local test but fails a global magnetic test proposed radial field (a) Method and calculation ∇· B = 1 r2 d dr(r2Br) = 0 (r > 0). Φsphere = 4πr2(K/r2) = 4πK . (b) Interpretation and further calculation I B · dA = 0 ⇒4πK = 0. K = 0 for the stated all-space model . Physical check Excluding a singular point from a differential calculation can hide a nonzero global flux.

Question 7

A radial inverse-square field passes a local test but fails a global magnetic test

For r greater than zero, a proposed field is 𝑩=Kr̂/r2\mathbf B=K\hat r/r^2. Assume it is intended to describe an ordinary magnetic field in all space, with no magnetic monopoles.

Diagram shown in the original SVG worksheet.

  1. Compute its divergence away from the origin and its flux through a sphere.

  2. Determine what K must be if every closed surface must have zero magnetic flux.

Question 7 - Solution

A radial inverse-square field passes a local test but fails a global magnetic test

Diagram shown in the original SVG worksheet.

(a) Method and calculation

∇⋅𝑩=1r2ddr(r2Br)=0(r>0).\nabla\cdot\mathbf B=\frac1{r^2}\frac d{dr}(r^2B_r)=0\quad(r>0).Φsphere=4πr2(K/r2)=4πK.\boxed{\Phi_{\mathrm{sphere}}=4\pi r^2(K/r^2)=4\pi K}.

(b) Interpretation and further calculation

∮𝑩⋅d𝑨=0⇒4πK=0.\oint\mathbf B\cdot d\mathbf A=0\Rightarrow4\pi K=0.K=0for the stated all-space model.\boxed{K=0\quad\text{for the stated all-space model}}.

Physical check

Excluding a singular point from a differential calculation can hide a nonzero global flux.