Gauss' Law for Magnetic Fields — Question 6

Section 32-1 · Physics pages 5182–5183

Question 6 Normal magnetic field is continuous across a material interface A thin pillbox straddles an interface. The magnetic field remains finite on both sides. Field 1 has magnitude .600 T and angle 60 degrees to the interface normal; field 2 makes 30 degrees to the same normal and has the same normal sign. B1 B2 Schematic; labels, not drawing lengths, specify the data. (a) Derive continuity of the normal field from shrinking pillbox flux. (b) Find the magnitude of field 2.
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Question 6 - Solution Normal magnetic field is continuous across a material interface B1 B2 (a) Method and calculation Φ = (B2n −B1n)A + O(h) = 0, h →0. B2n = B1n . (b) Interpretation and further calculation B2 cos 30◦= B1 cos 60◦. B2 = .600 1/2 √ 3/2 = .346410 T . Physical check Material response can change field direction and magnitude while preserving its normal component.

Question 6

Normal magnetic field is continuous across a material interface

A thin pillbox straddles an interface. The magnetic field remains finite on both sides. Field 1 has magnitude .600 T and angle 60 degrees to the interface normal; field 2 makes 30 degrees to the same normal and has the same normal sign.

Diagram shown in the original SVG worksheet.

  1. Derive continuity of the normal field from shrinking pillbox flux.

  2. Find the magnitude of field 2.

Question 6 - Solution

Normal magnetic field is continuous across a material interface

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Φ=(B2n−B1n)A+O(h)=0,h→0.\Phi=(B_{2n}-B_{1n})A+O(h)=0,\quad h\to0.B2n=B1n.\boxed{B_{2n}=B_{1n}}.

(b) Interpretation and further calculation

B2cos⁡30∘=B1cos⁡60∘.B_2\cos30^\circ=B_1\cos60^\circ.B2=.6001/23/2=.346410T.\boxed{B_2=.600\frac{1/2}{\sqrt3/2}=.346410\,T}.

Physical check

Material response can change field direction and magnitude while preserving its normal component.