Gauss' Law for Magnetic Fields — Question 8

Section 32-1 · Physics pages 5186–5187

Question 8 A magnetic flux tube expands as its field weakens A thin flux tube has negligible flux through its side wall. Its two end cuts are perpendicular to the local field. At the first cut B1=.800 T and A1=1.50 square centimeters; at the second B2=.300 T. B A1 A2 Schematic; labels, not drawing lengths, specify the data. (a) Find the second cross-sectional area. (b) If the second cut instead has its normal at 60 degrees to the field, find its geometric area for the same flux.
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Question 8 - Solution A magnetic flux tube expands as its field weakens B A1 A2 (a) Method and calculation −B1A1 + B2A2 = 0 ⇒A2 = B1A1/B2. A2 = 4.00 cm2 . (b) Interpretation and further calculation Φ = B2Atilted cos 60◦= B2A2. Atilted = 8.00 cm2 . Physical check A flux tube wall follows field lines; an arbitrary geometric tube would generally have side flux.

Question 8

A magnetic flux tube expands as its field weakens

A thin flux tube has negligible flux through its side wall. Its two end cuts are perpendicular to the local field. At the first cut B1=.800 T and A1=1.50 square centimeters; at the second B2=.300 T.

Diagram shown in the original SVG worksheet.

  1. Find the second cross-sectional area.

  2. If the second cut instead has its normal at 60 degrees to the field, find its geometric area for the same flux.

Question 8 - Solution

A magnetic flux tube expands as its field weakens

Diagram shown in the original SVG worksheet.

(a) Method and calculation

−B1A1+B2A2=0⇒A2=B1A1/B2.-B_1A_1+B_2A_2=0\Rightarrow A_2=B_1A_1/B_2.A2=4.00cm2.\boxed{A_2=4.00\,cm^2}.

(b) Interpretation and further calculation

Φ=B2Atiltedcos⁡60∘=B2A2.\Phi=B_2A_{\mathrm{tilted}}\cos60^\circ=B_2A_2.Atilted=8.00cm2.\boxed{A_{\mathrm{tilted}}=8.00\,cm^2}.

Physical check

A flux tube wall follows field lines; an arbitrary geometric tube would generally have side flux.