What Produces a Magnetic Field? — Question 3

Section 28-1 · Physics pages 4476–4477

Question 3 Current reversal separates a fixed background from a reversible source A vector sensor measures (8ˆx + 6ˆy) microtesla with current +I and (2ˆx −2ˆy) microtesla with current -I. Assume the background is constant and the source field is odd in I. I Bx −I 0 +I Schematic; labels, not drawing lengths, specify the data. (a) Extract the background vector and the source vector at +I. (b) Find their magnitudes and predict the reading at zero current.
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Question 3 - Solution Current reversal separates a fixed background from a reversible source I Bx −I 0 +I (a) Method and calculation⃗ B+ =⃗B0 +⃗Bs,⃗ B−=⃗B0 −⃗Bs.⃗ B0 = 1 2(⃗B+ +⃗B−) = (5ˆx + 2ˆy) µT,⃗ Bs = (3ˆx + 4ˆy) µT. (b) Interpretation and further calculation B0 = √ 29 µT, Bs = 5.00 µT.⃗ B(0) =⃗B0 = (5ˆx + 2ˆy) µT. Physical check This extraction fails if the background drifts between readings or the source has an even-in-current contribution.

Question 3

Current reversal separates a fixed background from a reversible source

A vector sensor measures (8x̂+6ŷ)(8\hat x+6\hat y) microtesla with current +I and (2x̂−2ŷ)(2\hat x-2\hat y) microtesla with current -I. Assume the background is constant and the source field is odd in I.

Diagram shown in the original SVG worksheet.

  1. Extract the background vector and the source vector at +I.

  2. Find their magnitudes and predict the reading at zero current.

Question 3 - Solution

Current reversal separates a fixed background from a reversible source

Diagram shown in the original SVG worksheet.

(a) Method and calculation

B→+=B→0+B→s,B→−=B→0−B→s.\vec B_+=\vec B_0+\vec B_s,\quad\vec B_-=\vec B_0-\vec B_s.B→0=12(B→++B→−)=(5x̂+2ŷ)μT,B→s=(3x̂+4ŷ)μT.\vec B_0=\tfrac12(\vec B_++\vec B_-)=(5\hat x+2\hat y)\,\mathrm{\mu T},\quad\vec B_s=(3\hat x+4\hat y)\,\mathrm{\mu T}.

(b) Interpretation and further calculation

B0=29μT,Bs=5.00μT.B_0=\sqrt{29}\,\mathrm{\mu T},\quad B_s=5.00\,\mathrm{\mu T}.B→(0)=B→0=(5x̂+2ŷ)μT.\vec B(0)=\vec B_0=(5\hat x+2\hat y)\,\mathrm{\mu T}.

Physical check

This extraction fails if the background drifts between readings or the source has an even-in-current contribution.