What Produces a Magnetic Field? — Question 2

Section 28-1 · Physics pages 4474–4475

Question 2 A transverse coil field can be calibrated by the direction of a compass A horizontal background field is B0ˆx. A coil produces κIˆy, with κ = 20.0 microtesla per ampere. At I=1.50 A, a small compass aligns at 30.0 degrees counterclockwise from +x. The compass does not appreciably alter the field. x y B0 κI⃗ B Schematic; labels, not drawing lengths, specify the data. (a) Find B0 and the magnitude of the total field. (b) Predict the direction when the current is reversed and explain why the two deflections have opposite signs.
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Question 2 - Solution A transverse coil field can be calibrated by the direction of a compass x y B0 κI⃗ B (a) Method and calculation tan θ = κI B0 ⇒B0 = 30.0 tan 30◦= 30 √ 3 µT. B = √ B2 0 + (κI)2 = 60.0 µT. (b) Interpretation and further calculation⃗ B(−I) = B0ˆx −κIˆy. θ(−I) = tan−1(−κI/B0) = −30.0◦. Physical check Current reversal reverses the coil contribution, while the fixed background remains unchanged.

Question 2

A transverse coil field can be calibrated by the direction of a compass

A horizontal background field is B0x̂B_0\hat x. A coil produces κIŷ\kappa I\hat y, with κ=20.0\kappa=20.0 microtesla per ampere. At I=1.50 A, a small compass aligns at 30.0 degrees counterclockwise from +x. The compass does not appreciably alter the field.

Diagram shown in the original SVG worksheet.

  1. Find B0 and the magnitude of the total field.

  2. Predict the direction when the current is reversed and explain why the two deflections have opposite signs.

Question 2 - Solution

A transverse coil field can be calibrated by the direction of a compass

Diagram shown in the original SVG worksheet.

(a) Method and calculation

tan⁡θ=κIB0⇒B0=30.0tan⁡30∘=303μT.\tan\theta=\frac{\kappa I}{B_0}\Rightarrow B_0=\frac{30.0}{\tan30^\circ}=30\sqrt3\,\mathrm{\mu T}.B=B02+(κI)2=60.0μT.B=\sqrt{B_0^2+(\kappa I)^2}=60.0\,\mathrm{\mu T}.

(b) Interpretation and further calculation

B→(−I)=B0x̂−κIŷ.\vec B(-I)=B_0\hat x-\kappa I\hat y.θ(−I)=tan⁡−1(−κI/B0)=−30.0∘.\theta(-I)=\tan^{-1}(-\kappa I/B_0)=-30.0^\circ.

Physical check

Current reversal reverses the coil contribution, while the fixed background remains unchanged.