What Produces a Magnetic Field? — Question 4

Section 28-1 · Physics pages 4478–4479

Question 4 A local magnetic null can coexist with several nonzero sources At point P, two fixed sources produce 3ˆx and 4ˆy microtesla. A control coil produces κIˆu, where κ = 2.00 microtesla per ampere and ˆu = −(3ˆx + 4ˆy)/5. x y 3 µT 4 µT control field Schematic; labels, not drawing lengths, specify the data. (a) Find the signed current that makes the total field at P zero. (b) If this current is increased by .100 A, find the residual field vector and magnitude. Does a null prove the sources are absent?
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Question 4 - Solution A local magnetic null can coexist with several nonzero sources x y 3 µT 4 µT control field (a) Method and calculation⃗ BP = (3ˆx + 4ˆy) + 2I[−(3ˆx + 4ˆy)/5] µT. 1 −2I/5 = 0 ⇒I = 2.50 A. (b) Interpretation and further calculation δ⃗B = κδIˆu = (−.120ˆx −.160ˆy) µT. |δ⃗B| = .200 µT;⃗ BP = 0̸ ⇒⃗B1 =⃗B2 = 0. Physical check A null is a vector cancellation at the specified point, not a statement that the entire region is field-free.

Question 4

A local magnetic null can coexist with several nonzero sources

At point P, two fixed sources produce 3x̂3\hat x and 4ŷ4\hat y microtesla. A control coil produces κIû\kappa I\hat u, where κ=2.00\kappa=2.00 microtesla per ampere and û=−(3x̂+4ŷ)/5\hat u=-(3\hat x+4\hat y)/5.

Diagram shown in the original SVG worksheet.

  1. Find the signed current that makes the total field at P zero.

  2. If this current is increased by .100 A, find the residual field vector and magnitude. Does a null prove the sources are absent?

Question 4 - Solution

A local magnetic null can coexist with several nonzero sources

Diagram shown in the original SVG worksheet.

(a) Method and calculation

B→P=(3x̂+4ŷ)+2I[−(3x̂+4ŷ)/5]μT.\vec B_P=(3\hat x+4\hat y)+2I[-(3\hat x+4\hat y)/5]\quad\mathrm{\mu T}.1−2I/5=0⇒I=2.50A.1-2I/5=0\Rightarrow I=2.50\,\mathrm A.

(b) Interpretation and further calculation

δB→=κδIû=(−.120x̂−.160ŷ)μT.\delta\vec B=\kappa\delta I\hat u=(-.120\hat x-.160\hat y)\,\mathrm{\mu T}.|δB→|=.200μT;B→P=0⇏B→1=B→2=0.|\delta\vec B|=.200\,\mathrm{\mu T};\quad\vec B_P=0\ \not\Rightarrow\ \vec B_1=\vec B_2=0.

Physical check

A null is a vector cancellation at the specified point, not a statement that the entire region is field-free.