What Produces a Magnetic Field? — Question 1

Section 28-1 · Physics pages 4472–4473

Question 1 Electrical neutrality does not determine whether a moving mixture carries current Two overlapping uniform particle streams have number density n each and charges +e and -e. In case A both move with velocity vˆx; in case B the positive stream moves with vˆx and the negative stream with −vˆx. Ignore their intrinsic moments. A B + − + − Schematic; labels, not drawing lengths, specify the data. (a) Find charge density and current density in each case. (b) Explain which case can act as a steady current source of magnetic field despite being electrically neutral.
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Question 1 - Solution Electrical neutrality does not determine whether a moving mixture carries current A B + − + − (a) Method and calculation ρA = ρB = ne −ne = 0.⃗ JA = nevˆx −nevˆx = 0,⃗ JB = nevˆx + nevˆx = 2nevˆx. (b) Interpretation and further calculation IA = 0, IB = 2nevA through a perpendicular area A. ρ = 0̸ ⇒⃗J = 0. Case B has nonzero conventional current; neutrality alone does not remove its magnetic effect. Physical check Charge density and current density are different source properties: one counts charge, the other weights charge by velocity.

Question 1

Electrical neutrality does not determine whether a moving mixture carries current

Two overlapping uniform particle streams have number density n each and charges +e and -e. In case A both move with velocity vx̂v\hat x; in case B the positive stream moves with vx̂v\hat x and the negative stream with −vx̂-v\hat x. Ignore their intrinsic moments.

Diagram shown in the original SVG worksheet.

  1. Find charge density and current density in each case.

  2. Explain which case can act as a steady current source of magnetic field despite being electrically neutral.

Question 1 - Solution

Electrical neutrality does not determine whether a moving mixture carries current

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ρA=ρB=ne−ne=0.\rho_A=\rho_B=ne-ne=0.J→A=nevx̂−nevx̂=0,J→B=nevx̂+nevx̂=2nevx̂.\vec J_A=nev\hat x-nev\hat x=0,\quad\vec J_B=nev\hat x+nev\hat x=2nev\hat x.

(b) Interpretation and further calculation

IA=0,IB=2nevAthrough a perpendicular area A.I_A=0,\quad I_B=2nevA\quad\text{through a perpendicular area }A.ρ=0⇏J→=0.\rho=0\ \not\Rightarrow\ \vec J=0.Case B has nonzero conventional current; neutrality alone does not remove its magnetic effect.

Physical check

Charge density and current density are different source properties: one counts charge, the other weights charge by velocity.