Line Integrals - Part II — Question 8

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Question 8

Let C:𝒓(t)=⟨cos⁡t,sin⁡t,t⟩,0≤t≤π2.C:\mathbf r(t)=\langle\cos t,\sin t,t\rangle, \qquad 0\le t\le\frac{\pi}{2}. Evaluate ∫Czdx+xdy+ydz.\int_C z\,dx+x\,dy+y\,dz.

Tasks

  1. Compute dxdx, dydy, and dzdz.

  2. Convert the line integral to one parameter and evaluate it.

  3. Verify the cancellation among the three contributions.

Original worksheet page 1: question and worked solution for 5-3-008
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Question 8 – Solution

Strategy. Treat each coordinate differential separately, then combine all three ordinary integrals.

Step 1: Differential data x=cos⁡t,y=sin⁡t,z=t,x=\cos t,\quad y=\sin t,\quad z=t, dx=−sin⁡tdt,dy=cos⁡tdt,dz=dt.dx=-\sin t\,dt,\quad dy=\cos t\,dt,\quad dz=dt.

See the diagram in the original worksheet below.

Step 2: Evaluate ∫Czdx+xdy+ydz=∫0π/2(−tsint+cos⁡2t+sint)dt.\begin{align*} \int_C z\,dx+x\,dy+y\,dz &=\int_0^{\pi/2} \left(-t\sin t+\cos^2t+\sin t\right)dt. \end{align*} The three contributions are ∫0π/2−tsin⁡tdt=−1,∫0π/2cos⁡2tdt=π4,∫0π/2sin⁡tdt=1.\int_0^{\pi/2}-t\sin t\,dt=-1,\quad \int_0^{\pi/2}\cos^2t\,dt=\frac{\pi}{4},\quad \int_0^{\pi/2}\sin t\,dt=1. Hence ∫Czdx+xdy+ydz=π4.\boxed{\int_C z\,dx+x\,dy+y\,dz=\frac{\pi}{4}}.

Verification The first and third contributions cancel exactly, leaving only ∫0π/2cos⁡2tdt=π/4\int_0^{\pi/2}\cos^2t\,dt=\pi/4.

Original worksheet page 2: question and worked solution for 5-3-008

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