Lagrange Multipliers — Question 4

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Question 4

A rectangular box has positive side lengths x,y,zx,y,z and fixed sum of its three side lengths x+y+z=12.x+y+z=12. Find the dimensions giving the largest volume V=xyzV=xyz.

Tasks

  1. Solve the three-variable Lagrange multiplier system.

  2. Find the maximum volume.

  3. Verify global maximality by checking the boundary of the closed simplex and using an inequality.

Original worksheet page 1: question and worked solution for 3-5-004
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Question 4 – Solution

Strategy. The multiplier equations force equal positive side lengths; then compare with the zero-volume boundary and verify by AM–GM.

Step 1: Lagrange system For g=x+y+zg=x+y+z, ∇V=⟨yz,xz,xy⟩=λ⟨1,1,1⟩.\nabla V=\left\langle yz,xz,xy\right\rangle =\lambda\left\langle 1,1,1\right\rangle. Because x,y,z>0x,y,z>0, equality of the three components gives yz=xz=xy,yz=xz=xy, and division by positive factors yields x=y=zx=y=z. The constraint then gives x=y=z=4.\boxed{x=y=z=4}.

Step 2: Volume Vmax=4⋅4⋅4=64.\boxed{V_{\max}=4\cdot 4\cdot 4=64}.

Step 3: Global verification Allowing x,y,z≥0x,y,z\ge 0 closes the feasible simplex. Its boundary has at least one zero side, so V=0V=0 there. In the positive interior, AM–GM gives x+y+z3≥(xyz)1/3.\frac{x+y+z}{3}\ge(xyz)^{1/3}. Since the left side is 44, xyz≤64,xyz\le 64, with equality only when x=y=zx=y=z. Thus the Lagrange candidate is the unique positive absolute maximizer.

Original worksheet page 2: question and worked solution for 3-5-004

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