Spherical Coordinates — Question 7

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Question 7

Find the distance between P=(3,π/6,π/3)P=(3,\pi/6,\pi/3) and Q=(5,5π/6,2π/3)Q=(5,5\pi/6,2\pi/3) in spherical coordinates without first converting both points to Cartesian form.

Tasks

  1. Derive the angle between their radial directions.

  2. Compute the distance exactly.

  3. Check that the result obeys the triangle bounds.

Original worksheet page 1: question and worked solution for 1-13-007
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Question 7 – Solution

Strategy. Take the dot product of the two unit radial directions and apply the three-dimensional law of cosines.

Step 1: Direction angle If γ\gamma is the angle between the radial directions, then cos⁡γ=cos⁡ϕ1cos⁡ϕ2+sin⁡ϕ1sin⁡ϕ2cos⁡(θ1−θ2).\cos\gamma=\cos\phi_1\cos\phi_2+\sin\phi_1\sin\phi_2\cos(\theta_1-\theta_2). Here cos⁡ϕ1cos⁡ϕ2=−1/4\cos\phi_1\cos\phi_2=-1/4, sin⁡ϕ1sin⁡ϕ2=3/4\sin\phi_1\sin\phi_2=3/4, and cos⁡(−2π/3)=−1/2\cos(-2\pi/3)=-1/2, so cos⁡γ=−5/8\cos\gamma=-5/8.

Step 2: Distance Therefore d2=ρ12+ρ22−2ρ1ρ2cos⁡γ=9+25−30(−5/8)=2114.d^2=\rho_1^2+\rho_2^2-2\rho_1\rho_2\cos\gamma=9+25-30(-5/8)=\frac{211}{4}. Thus d=2112.\boxed{d=\frac{\sqrt{211}}{2}}.

Verification. The triangle inequality requires |5−3|≤d≤5+3|5-3|\le d\le 5+3. Numerically d≈7.26d\approx 7.26, which lies between 22 and 88.

Original worksheet page 2: question and worked solution for 1-13-007

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