Absolute Convergence and Divergence — Question 5

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Question 5

Consider ∑n=1∞(−1)nn\displaystyle\sum_{n=1}^{\infty}\frac{(-1)^n}{\sqrt n}.

  1. Verify ordinary convergence.

  2. Test the absolute-value series with the pp-series rule.

  3. Classify convergence and give an error bound.

Original worksheet page 1: question and worked solution for 4-9-005
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Question 5 – Solution

Step 1: Apply the AST.

With bn=1/nb_n=1/\sqrt n, positivity, decrease, and bn→0b_n\to0 all hold. Thus the series converges.

Step 2: Test absolute convergence.

∑|(−1)nn|=∑1n1/2,\sum\left|\frac{(-1)^n}{\sqrt n}\right|=\sum\frac1{n^{1/2}}, which diverges because p=1/2≤1p=1/2\le1.

Step 3: Classify and estimate.

The convergence is conditional, and |S−sN|≤1N+1.|S-s_N|\le\frac1{\sqrt{N+1}}.

Original worksheet page 2: question and worked solution for 4-9-005

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