Series - The Basics — Question 6

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Question 6

Consider ∑n=1∞(−1)n\displaystyle\sum_{n=1}^{\infty}(-1)^n.

  1. List the first six terms and partial sums.

  2. Prove that the sequence of partial sums is bounded but divergent.

  3. Apply the nth-term test and explain why bounded partial sums alone do not imply convergence.

Original worksheet page 1: question and worked solution for 4-3-006
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Question 6 – Solution

Step 1: Distinguish terms from partial sums.

The series terms are an=(−1)na_n=(-1)^n, so the first six are −1,1,−1,1,−1,1-1,1,-1,1,-1,1. Adding successively gives the partial sums −1,0,−1,0,−1,0,….-1,0,-1,0,-1,0,\ldots. More precisely, s2k=0,s2k−1=−1.s_{2k}=0,\qquad s_{2k-1}=-1.

Step 2: Test convergence of the partial sums.

The sequence (sN)(s_N) is bounded between −1-1 and 00, but s2k=0→0s_{2k}=0\to0 while s2k−1=−1→−1s_{2k-1}=-1\to-1. Since these subsequences have different limits, (sN)(s_N) does not converge. By definition, the series therefore diverges.

Step 3: Apply the nth-term test as a check.

The terms (−1)n(-1)^n do not approach zero, so the nth-term test also proves divergence immediately. Indeed, if sN→Ss_N\to S, then aN=sN−sN−1→S−S=0a_N=s_N-s_{N-1}\to S-S=0. This example shows that bounded partial sums are not enough; the partial sums must approach one number.

Original worksheet page 2: question and worked solution for 4-3-006

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