Binomial Series — Question 8

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Question 8

Let mm be a nonnegative integer. Explain algebraically why the generalized binomial series for (1+x)m(1+x)^m terminates, and recover the ordinary finite Binomial Theorem. Illustrate with m=4m=4.

Original worksheet page 1: question and worked solution for 4-18-008
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Question 8 – Solution

Step 1: Examine the generalized coefficient.

(mn)=m(m−1)⋯(m−n+1)n!.\binom{m}{n}=\frac{m(m-1)\cdots(m-n+1)}{n!}. If n=m+1n=m+1, the numerator includes the factor m−m=0m-m=0. For every n>mn>m, it still includes that zero factor. Hence (mn)=0(n>m).\binom{m}{n}=0\qquad(n>m).

Step 2: Recover the finite theorem.

The formally infinite series therefore reduces to (1+x)m=∑n=0m(mn)xn.\boxed{(1+x)^m=\sum_{n=0}^{m}\binom{m}{n}x^n}. Because this is a polynomial identity, it is valid for every real (and complex) xx; there is no finite radius restriction.

Step 3: Illustrate with m=4m=4.

(1+x)4=1+4x+6x2+4x3+x4.(1+x)^4=1+4x+6x^2+4x^3+x^4. The next coefficient is (45)=0\binom45=0, so no higher powers occur.

Original worksheet page 2: question and worked solution for 4-18-008

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