Power Series — Question 6

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Question 6

Determine the radius and interval of convergence of ∑n=0∞xn/n!\displaystyle\sum_{n=0}^{\infty}x^n/n!. Explain why the factorial denominator allows every real xx.

Original worksheet page 1: question and worked solution for 4-14-006
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Question 6 – Solution

Step 1: Apply the Ratio Test for a fixed xx.

|xn+1/(n+1)!xn/n!|=|x|n+1→0.\left|\frac{x^{n+1}/(n+1)!}{x^n/n!}\right|=\frac{|x|}{n+1}\longrightarrow0. For every fixed real xx, the limit is 0<10<1.

Step 2: State the convergence set.

The series converges absolutely for all x∈ℝx\in\mathbb R. Thus R=∞,(−∞,∞).\boxed{R=\infty},\qquad \boxed{(-\infty,\infty)}. There are no finite endpoints to test.

Step 3: Interpret the factorial.

Each ratio contains the growing divisor n+1n+1, which eventually dominates any fixed |x||x|. The series is the familiar expansion ex=∑xn/n!e^x=\sum x^n/n!.

Original worksheet page 2: question and worked solution for 4-14-006

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