Let
and
.
Use the Integral Test remainder theorem to give a two-sided bound for
.
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Question 8 –
Solution
Step 1: Check monotonicity.
For
,
Thus
is positive, continuous, and decreasing on the needed interval.
Step 2: Find the
antiderivative.
Integration by parts gives
Step 3: Apply both
remainder bounds.
so
The upper bound is a decreasing integral majorant for the full omitted
tail; no extra first-term adjustment is needed under this standard
formulation.
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