Estimating the Value of a Series — Question 6

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Question 6

The Leibniz series is π4=∑n=0∞(−1)n2n+1\displaystyle\frac\pi4=\sum_{n=0}^{\infty}\frac{(-1)^n}{2n+1}. If exactly MM terms are used (indices 00 through M−1M-1), find the least MM certified by a next-term bound strictly below 10−410^{-4}.

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Question 6 – Solution

Step 1: Identify the first omitted term.

With MM terms, the final included index is M−1M-1, so the first omitted term has index MM and magnitude 1/(2M+1)1/(2M+1).

Step 2: Apply the alternating estimate.

|R|≤12M+1.|R|\le\frac1{2M+1}. We need 12M+1<10−4⇔2M+1>10,000⇔M>4999.5.\frac1{2M+1}<10^{-4}\iff 2M+1>10{,}000\iff M>4999.5. Thus the least integer is M=5000\boxed{M=5000}.

Step 3: Verify minimality.

With 49994999 terms the bound is 1/9999>10−41/9999>10^{-4}; with 50005000 terms it is 1/10001<10−41/10001<10^{-4}. This large count illustrates the slow convergence of the Leibniz series.

Original worksheet page 2: question and worked solution for 4-13-006

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