Ratio Test — Question 7

PDF ↗

Question 7

Determine whether ∑n=1∞n!n10\displaystyle\sum_{n=1}^{\infty}\frac{n!}{n^{10}} converges or diverges.

  1. Simplify an+1/ana_{n+1}/a_n.

  2. Use its limiting behavior to justify the conclusion.

  3. Explain why the nth-term test also applies.

Original worksheet page 1: question and worked solution for 4-10-007
Show solutionHide solution

Question 7 – Solution

Step 1: Compute the ratio.

an+1an=(n+1)!(n+1)10n10n!=(n+1)(nn+1)10=n(1+1n)−9.\begin{align*} \frac{a_{n+1}}{a_n}&=\frac{(n+1)!}{(n+1)^{10}}\frac{n^{10}}{n!}=(n+1)\left(\frac{n}{n+1}\right)^{10}\\&=n\left(1+\frac1n\right)^{-9}. \end{align*}

Step 2: Evaluate its behavior.

The factor (1+1/n)−9→1(1+1/n)^{-9}\to1, while n→∞n\to\infty. Hence L=∞>1L=\infty>1.

Conclusion.

The series diverges. Its terms eventually grow rather than approach zero, so the nth-term divergence test confirms the result. A factorial eventually dominates every fixed power n10n^{10}.

Original worksheet page 2: question and worked solution for 4-10-007

Original worksheet layout. Use Enlarge or open the PDF for a closer view.