Arc Length with Polar Coordinates — Question 8

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Question 8

Problem

Explain why integrating the rose r=cos⁡3θr=\cos3\theta from 00 to 2π2\pi overcounts its geometric length.

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Original worksheet page 1: question and worked solution for 3-9-008
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Question 8 – Solution

See the diagram in the original worksheet below.

Solution

  1. Differentiate the polar radius to obtain r′=dr/dθr'=dr/d\theta and choose an interval that traces the requested arc exactly once.

  2. Use the polar arc-length formula L=∫abr2+(drdθ)2dθ.L=\int_a^b\sqrt{r^2+\left(\frac{dr}{d\theta}\right)^2}\,d\theta. Simplify the expression under the square root before evaluating or reporting the integral.

  3. For odd 33, the full curve is completed on 0≤θ≤π0\le\theta\le\pi; the next π\pi retraces it because negative radius duplicates opposite points.

  4. The 00 to 2π2\pi integral counts every petal twice.

Original worksheet page 2: question and worked solution for 3-9-008

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