Surface Area with Polar Coordinates — Question 5

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Question 5

Problem

A student proposes using only 0≤θ≤π/20\le\theta\le\pi/2 when the circle r=4sin⁡θr=4\sin\theta rotates about the xx-axis. Explain why that omits part of the surface and give a correct interval.

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Original worksheet page 1: question and worked solution for 3-10-005
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Question 5 – Solution

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Solution

  1. Compute the polar arc-length element ds=r2+(drdθ)2dθ.ds=\sqrt{r^2+\left(\frac{dr}{d\theta}\right)^2}\,d\theta.

  2. Express the radius of rotation as a nonnegative distance: use |rsin⁡θ||r\sin\theta| for the xx-axis and |rcos⁡θ||r\cos\theta| for the yy-axis. Then apply S=2π∫ab(radius to the axis)ds,S=2\pi\int_a^b(\text{radius to the axis})\,ds, over an interval that generates the surface exactly once.

  3. The interval 0≤θ≤π/20\le\theta\le\pi/2 traces only the right semicircle; rotation preserves the xx-coordinate, so the left half is not duplicated.

  4. Use 0≤θ≤π\boxed{0\le\theta\le\pi} to trace the full generating circle once.

Original worksheet page 2: question and worked solution for 3-10-005

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