Types of Infinity — Question 1

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Question 1

Prove that limx→∞ln⁡xx=0.\lim_{x\to\infty}\frac{\ln x}{x}=0.

Original worksheet page 1: question and worked solution for 7-7-001
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Question 1 - Solution

We compare the growth rates of the numerator and denominator.

For x>0x>0, both ln⁡x\ln x and xx are differentiable. Apply L’Hôpital’s Rule to the limit limx→∞ln⁡xx.\lim_{x\to\infty}\frac{\ln x}{x}.

Differentiate the numerator and denominator: ddx(ln⁡x)=1x,ddx(x)=1.\frac{d}{dx}(\ln x)=\frac{1}{x}, \qquad \frac{d}{dx}(x)=1.

Thus, limx→∞ln⁡xx=limx→∞1/x1=limx→∞1x.\lim_{x\to\infty}\frac{\ln x}{x} = \lim_{x\to\infty}\frac{1/x}{1} = \lim_{x\to\infty}\frac{1}{x}.

From basic limits, limx→∞1x=0.\lim_{x\to\infty}\frac{1}{x}=0.

Therefore, limx→∞ln⁡xx=0.\lim_{x\to\infty}\frac{\ln x}{x}=0.

0\boxed{0}

Original worksheet page 2: question and worked solution for 7-7-001

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