Differentials — Question 3

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Question 3

The length of the side of a cube is measured to be 10 cm with a possible error of 0.2 cm.

  • (a) Use differentials to approximate the maximum error in the calculated surface area of the cube.

  • (b) Estimate the relative error and the percentage error in the surface area.

Original worksheet page 1: question and worked solution for 4-12-003
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Question 3 - Solution

Let the surface area of the cube be: S=6x2S = 6x^2 where xx is the length of a side.

(a) Approximate error using differentials:

dS=dSdxdx=12xdxdS = \frac{dS}{dx} \, dx = 12x \, dx dS=12(10)(0.2)=24cm2dS = 12(10)(0.2) = 24 \, \text{cm}^2

(b) Relative error: dSS=246(10)2=24600=0.04\frac{dS}{S} = \frac{24}{6(10)^2} = \frac{24}{600} = 0.04

Percentage error: 0.04×100=4%0.04 \times 100 = \boxed{4\%}

Final Answer:

  • Maximum error in surface area: 24cm2\boxed{24 \, \text{cm}^2}

  • Relative error: 0.04\boxed{0.04}

  • Percentage error: 4%\boxed{4\%}

Original worksheet page 2: question and worked solution for 4-12-003

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