Linear Approximations — Question 9

Question 9 - Solution

(a) Let $f(x) = \ln(x)$, and choose $a = 1$ since $\ln(1) = 0$ is easy to compute.

$$f(a) = \ln(1) = 0, \quad f'(x) = \frac{1}{x}, \quad f'(1) = 1$$

(b) Linear approximation: $$L(x) = f(a) + f'(a)(x - a) = 0 + 1(x - 1) = x - 1$$

(c) Estimate $\ln(1.05)$ using: $$L(1.05) = 1.05 - 1 = 0.05$$

Actual: $\ln(1.05) \approx 0.04879$

Conclusion: $$\boxed{\ln(1.05) \approx 0.05} \quad \text{(Linear Approximation)}$$