The Eightfold Way — Question 7

Section 44-6 · Physics pages 7404–7405

Question 7 An octet mass relation can be tested with a signed residual Use the approximate baryon octet relation 2(MN + MΞ) = 3MΛ + MΣ. Rest energies are 939, 1318 and 1116 MeV for N, Xi and Lambda. A comparison Sigma rest energy is 1193 MeV. Y I3 n p Σ− Σ0, Λ Σ+ Ξ− Ξ0 Light-flavor weight diagram: horizontal coordinate I3, vertical coordinate Y = B + S; axis origins are offset for clarity. (a) Predict the Sigma rest energy. (b) Compute the residual of the full mass relation using the comparison value, and the fractional Sigma prediction error.
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Question 7 - Solution An octet mass relation can be tested with a signed residual Y I3 n p Σ− Σ0, Λ Σ+ Ξ− Ξ0 (a) Method and calculation MΣ = 2(MN + MΞ) −3MΛ. MΣc2 = 2(939 + 1318) −3(1116) = 1166 MeV . (b) Interpretation and further calculation [2(MN + MΞ) −3MΛ −MΣ]c2 = −27 MeV . (1193 −1166)/1193 = 0.0226320 = 2.26320% . Physical check Explicitly retaining the sign prevents confusing an underprediction of Sigma mass with a positive relation residual.

Question 7

An octet mass relation can be tested with a signed residual

Use the approximate baryon octet relation 2(MN+MΞ)=3MΛ+MΣ2(M_N+M_\Xi)=3M_\Lambda+M_\Sigma. Rest energies are 939, 1318 and 1116 MeV for N, Xi and Lambda. A comparison Sigma rest energy is 1193 MeV.

Diagram shown in the original SVG worksheet.

  1. Predict the Sigma rest energy.

  2. Compute the residual of the full mass relation using the comparison value, and the fractional Sigma prediction error.

Question 7 - Solution

An octet mass relation can be tested with a signed residual

Diagram shown in the original SVG worksheet.

(a) Method and calculation

MΣ=2(MN+MΞ)−3MΛ.M_\Sigma=2(M_N+M_\Xi)-3M_\Lambda.MΣc2=2(939+1318)−3(1116)=1166MeV.\boxed{M_\Sigma c^2=2(939+1318)-3(1116)=1166\ {\mathrm{MeV}}}.

(b) Interpretation and further calculation

[2(MN+MΞ)−3MΛ−MΣ]c2=−27MeV.\boxed{[2(M_N+M_\Xi)-3M_\Lambda-M_\Sigma]c^2=-27\ {\mathrm{MeV}}}.(1193−1166)/1193=0.0226320=2.26320%.\boxed{(1193-1166)/1193=0.0226320=2.26320\%}.

Physical check

Explicitly retaining the sign prevents confusing an underprediction of Sigma mass with a positive relation residual.