The Eightfold Way — Question 6

Section 44-6 · Physics pages 7402–7403

Question 6 Equal spacing provides an approximate decuplet mass prediction In an illustrative isospin-averaged decuplet, the first three strangeness rows have rest energies 1230, 1380 and 1530 MeV. Assume equal spacing per additional unit of negative strangeness. A comparison value for the last row is 1672 MeV. Y I3 ∆− ∆0 ∆+ ∆++ Σ∗− Σ∗0 Σ∗+ Ξ∗− Ξ∗0 Ω− Light-flavor weight diagram: horizontal coordinate I3, vertical coordinate Y = B + S; axis origins are offset for clarity. (a) Predict the last mass and verify the two input spacings. (b) Find the comparison-minus-prediction residual and fractional discrepancy relative to the comparison mass.
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Question 6 - Solution Equal spacing provides an approximate decuplet mass prediction Y I3 ∆− ∆0 ∆+ ∆++ Σ∗− Σ∗0 Σ∗+ Ξ∗− Ξ∗0 Ω− (a) Method and calculation δM = 1380 −1230 = 1530 −1380 = 150 MeV/c2 . MΩc2 = 1530 + 150 = 1680 MeV . (b) Interpretation and further calculation r = (1672 −1680) MeV = −8 MeV . |r|/1672 = 0.00478469 = 0.478469% . Physical check Flavor symmetry is approximate; equal spacing is a useful mass relation, not an exact conservation law.

Question 6

Equal spacing provides an approximate decuplet mass prediction

In an illustrative isospin-averaged decuplet, the first three strangeness rows have rest energies 1230, 1380 and 1530 MeV. Assume equal spacing per additional unit of negative strangeness. A comparison value for the last row is 1672 MeV.

Diagram shown in the original SVG worksheet.

  1. Predict the last mass and verify the two input spacings.

  2. Find the comparison-minus-prediction residual and fractional discrepancy relative to the comparison mass.

Question 6 - Solution

Equal spacing provides an approximate decuplet mass prediction

Diagram shown in the original SVG worksheet.

(a) Method and calculation

δM=1380−1230=1530−1380=150MeV/c2.\boxed{\delta M=1380-1230=1530-1380=150\ {\mathrm{MeV}}/c^2}.MΩc2=1530+150=1680MeV.\boxed{M_{\Omega}c^2=1530+150=1680\ {\mathrm{MeV}}}.

(b) Interpretation and further calculation

r=(1672−1680)MeV=−8MeV.\boxed{r=(1672-1680)\ {\mathrm{MeV}}=-8\ {\mathrm{MeV}}}.|r|/1672=0.00478469=0.478469%.\boxed{|r|/1672=0.00478469=0.478469\%}.

Physical check

Flavor symmetry is approximate; equal spacing is a useful mass relation, not an exact conservation law.