The Leptons — Question 8

Section 44-3 · Physics pages 7346–7347

Question 8 An invisible decay width counts light neutrino species conditionally A neutral resonance has total width 2.500 ± .010 GeV and visible width 2.000 ± .008 GeV, with independent uncertainties. A model predicts .167 GeV per light neutrino-antineutrino species, with negligible model uncertainty. Z visible ν¯ν Schematic; labels, not drawing lengths, specify the data. (a) Infer invisible width and its uncertainty. (b) Infer the effective number of light species and state the assumptions needed to interpret it as a species count.
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Question 8 - Solution An invisible decay width counts light neutrino species conditionally Z visible ν¯ν (a) Method and calculation Γinv = Γtotal −Γvis = .500 GeV . σinv = √ .0102 + .0082 = .0128062 GeV . (b) Interpretation and further calculation Neff= .500/.167 = 2.99401, σN = .0128062/.167 = 0.0766841 . Γinv = NνΓν¯ν only if no other invisible channels contribute. Physical check The inference counts species light enough to be produced and with the assumed coupling strength. It does not rule out heavy or differently coupled neutral particles.

Question 8

An invisible decay width counts light neutrino species conditionally

A neutral resonance has total width 2.500±.0102.500\pm.010 GeV and visible width 2.000±.0082.000\pm.008 GeV, with independent uncertainties. A model predicts .167 GeV per light neutrino-antineutrino species, with negligible model uncertainty.

Diagram shown in the original SVG worksheet.

  1. Infer invisible width and its uncertainty.

  2. Infer the effective number of light species and state the assumptions needed to interpret it as a species count.

Question 8 - Solution

An invisible decay width counts light neutrino species conditionally

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Γinv=Γtotal−Γvis=.500GeV.\boxed{\Gamma_{\mathrm{inv}}=\Gamma_{\mathrm{total}}-\Gamma_{\mathrm{vis}}=.500\,\mathrm{GeV}}.σinv=.0102+.0082=.0128062GeV.\boxed{\sigma_{\mathrm{inv}}=\sqrt{.010^2+.008^2}=.0128062\,\mathrm{GeV}}.

(b) Interpretation and further calculation

Neff=.500/.167=2.99401,σN=.0128062/.167=0.0766841.\boxed{N_{\mathrm{eff}}=.500/.167=2.99401,\quad\sigma_N=.0128062/.167=0.0766841}.Γinv=NνΓνν‾only if no other invisible channels contribute.\Gamma_{\mathrm{inv}}=N_\nu\Gamma_{\nu\bar\nu}\quad\text{only if no other invisible channels contribute}.

Physical check

The inference counts species light enough to be produced and with the assumed coupling strength. It does not rule out heavy or differently coupled neutral particles.