The Leptons — Question 7

Section 44-3 · Physics pages 7344–7345

Question 7 Averaging oscillation phases reveals the mixing amplitude A broad energy spectrum averages sin2 ϕ to 1/2 in the supplied two-flavor survival law. The measured average survival is .700 ± .020, with standard uncertainty. Assume no other losses. L/E P Schematic; labels, not drawing lengths, specify the data. (a) Infer sin2(2θ) and its uncertainty. (b) Find the two possible mixing angles between 0 and 90 degrees and explain the degeneracy.
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Question 7 - Solution Averaging oscillation phases reveals the mixing amplitude L/E P (a) Method and calculation ⟨P⟩= 1 −1 2 sin2(2θ) ⇒sin2(2θ) = 2(1 −.700) = .600 . σsin2(2θ) = 2(.020) = .040 . (b) Interpretation and further calculation 2θ = sin−1 √ .600 or 180◦−sin−1 √ .600. θ = 25.3842◦or 64.6158◦. Physical check The survival probability is invariant under theta changing to 90 degrees minus theta. A phase-averaged measurement loses oscillation-length information.

Question 7

Averaging oscillation phases reveals the mixing amplitude

A broad energy spectrum averages sin⁡2ϕ\sin^2\phi to 1/2 in the supplied two-flavor survival law. The measured average survival is .700±.020.700\pm.020, with standard uncertainty. Assume no other losses.

Diagram shown in the original SVG worksheet.

  1. Infer sin⁡2(2θ)\sin^2(2\theta) and its uncertainty.

  2. Find the two possible mixing angles between 0 and 90 degrees and explain the degeneracy.

Question 7 - Solution

Averaging oscillation phases reveals the mixing amplitude

Diagram shown in the original SVG worksheet.

(a) Method and calculation

⟨P⟩=1−12sin⁡2(2θ)⇒sin⁡2(2θ)=2(1−.700)=.600.\langle P\rangle=1-\tfrac12\sin^2(2\theta)\Rightarrow\boxed{\sin^2(2\theta)=2(1-.700)=.600}.σsin⁡2(2θ)=2(.020)=.040.\boxed{\sigma_{\sin^2(2\theta)}=2(.020)=.040}.

(b) Interpretation and further calculation

2θ=sin⁡−1.600or180∘−sin⁡−1.600.2\theta=\sin^{-1}\sqrt{.600}\ \text{or}\ 180^\circ-\sin^{-1}\sqrt{.600}.θ=25.3842∘or64.6158∘.\boxed{\theta=25.3842^\circ\ \text{or}\ 64.6158^\circ}.

Physical check

The survival probability is invariant under theta changing to 90 degrees minus theta. A phase-averaged measurement loses oscillation-length information.