Thermonuclear Fusion: The Basic Process — Question 8

Section 43-5 · Physics pages 7246–7247

Question 8 Fuel depletion makes the cumulative fusion yield sublinear in time In a fixed volume with constant temperature, equal reactant densities start at nD = nT = n0. Their common density obeys dn/dt = −Kn2, with no replenishment. Let Kn0 = .200 s−1. t n Schematic; labels, not drawing lengths, specify the data. (a) Solve for n(t) and the fraction of either initial species consumed. (b) Find that fraction after 5.00 s and compare the cumulative event count with the constant-initial-rate estimate.
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Question 8 - Solution Fuel depletion makes the cumulative fusion yield sublinear in time t n (a) Method and calculation ∫n n0 dn′ n′2 = −Kt ⇒n(t) = n0 1 + Kn0t . fconsumed = 1 −n/n0 = Kn0t 1 + Kn0t . (b) Interpretation and further calculation f(5) = 1/2, Nevents/V = n0 −n = n0/2 . R0t = Kn2 0t = n0 ⇒initial-rate estimate is twice the actual yield . Physical check One atom of each species is consumed per event. Constant reactivity is imposed; temperature evolution is outside this depletion model.

Question 8

Fuel depletion makes the cumulative fusion yield sublinear in time

In a fixed volume with constant temperature, equal reactant densities start at nD=nT=n0n_D=n_T=n_0. Their common density obeys dn/dt=−Kn2dn/dt=-Kn^2, with no replenishment. Let Kn0=.200s−1Kn_0=.200\,\mathrm{s^{-1}}.

Diagram shown in the original SVG worksheet.

  1. Solve for n(t) and the fraction of either initial species consumed.

  2. Find that fraction after 5.00 s and compare the cumulative event count with the constant-initial-rate estimate.

Question 8 - Solution

Fuel depletion makes the cumulative fusion yield sublinear in time

Diagram shown in the original SVG worksheet.

(a) Method and calculation

∫n0ndn′n′2=−Kt⇒n(t)=n01+Kn0t.\int_{n_0}^{n}\frac{dn\prime}{n\prime{}^2}=-Kt\Rightarrow\boxed{n(t)=\frac{n_0}{1+Kn_0t}}.fconsumed=1−n/n0=Kn0t1+Kn0t.\boxed{f_{\mathrm{consumed}}=1-n/n_0=\frac{Kn_0t}{1+Kn_0t}}.

(b) Interpretation and further calculation

f(5)=1/2,Nevents/V=n0−n=n0/2.\boxed{f(5)=1/2,\quad N_{\mathrm{events}}/V=n_0-n=n_0/2}.R0t=Kn02t=n0⇒initial-rate estimate is twice the actual yield.R_0t=Kn_0^2t=n_0\Rightarrow\boxed{\text{initial-rate estimate is twice the actual yield}}.

Physical check

One atom of each species is consumed per event. Constant reactivity is imposed; temperature evolution is outside this depletion model.