Thermonuclear Fusion: The Basic Process — Question 7

Section 43-5 · Physics pages 7244–7245

Question 7 An unequal fuel mixture reduces fusion rate at fixed total density Let nD = xn and nT = (1 −x)n at fixed total ion density n and fixed temperature. Reaction rate density is R = nDnT ⟨σv⟩. x R 0 1/2 1 Schematic; labels, not drawing lengths, specify the data. (a) Find the mixture fraction x that maximizes R and show it is a maximum. (b) For x=.700 find the fraction of the maximum rate, and explain why changing total density is a different comparison.
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Question 7 - Solution An unequal fuel mixture reduces fusion rate at fixed total density x R 0 1/2 1 (a) Method and calculation R = x(1 −x)n2⟨σv⟩, dR dx = (1 −2x)n2⟨σv⟩. xmax = 1/2, Rmax = 1 4n2⟨σv⟩, R′′ < 0 . (b) Interpretation and further calculation R(.700)/Rmax = 4(.700)(.300) = .840 . R ∝n2 at fixed composition and temperature. Physical check The optimization applies only to a uniform two-species mixture at fixed total density and reactivity. Fuel evolution and impurities can change those constraints.

Question 7

An unequal fuel mixture reduces fusion rate at fixed total density

Let nD=xnn_D=xn and nT=(1−x)nn_T=(1-x)n at fixed total ion density n and fixed temperature. Reaction rate density is R=nDnT⟨σv⟩R=n_Dn_T\langle\sigma v\rangle.

Diagram shown in the original SVG worksheet.

  1. Find the mixture fraction x that maximizes R and show it is a maximum.

  2. For x=.700 find the fraction of the maximum rate, and explain why changing total density is a different comparison.

Question 7 - Solution

An unequal fuel mixture reduces fusion rate at fixed total density

Diagram shown in the original SVG worksheet.

(a) Method and calculation

R=x(1−x)n2⟨σv⟩,dRdx=(1−2x)n2⟨σv⟩.R=x(1-x)n^2\langle\sigma v\rangle,\quad\frac{dR}{dx}=(1-2x)n^2\langle\sigma v\rangle.xmax=1/2,Rmax=14n2⟨σv⟩,R′′<0.\boxed{x_{\max}=1/2,\quad R_{\max}=\frac14n^2\langle\sigma v\rangle,\quad R^{\prime\prime}<0}.

(b) Interpretation and further calculation

R(.700)/Rmax=4(.700)(.300)=.840.\boxed{R(.700)/R_{\max}=4(.700)(.300)=.840}.R∝n2at fixed composition and temperature.\boxed{R\propto n^2}\quad\text{at fixed composition and temperature}.

Physical check

The optimization applies only to a uniform two-species mixture at fixed total density and reactivity. Fuel evolution and impurities can change those constraints.