Nuclear Models — Question 4

Section 42-8 · Physics pages 7138–7139

Question 4 Competition between Coulomb and asymmetry energies favors neutron excess At fixed A, ignore neutron-proton rest-mass difference and pairing. Approximate the Z-dependent mass energy by F(Z) = acZ2A−1/3 + aa(A −2Z)2/A. Treat Z as continuous, with ac = .700 MeV and aa = 23.0 MeV. Z F Z∗ Schematic; labels, not drawing lengths, specify the data. (a) Minimize F to derive the preferred Z. (b) Evaluate it for A=100 and infer the approximate neutron-to-proton ratio. Check that the stationary point is a minimum.
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Question 4 - Solution Competition between Coulomb and asymmetry energies favors neutron excess Z F Z∗ (a) Method and calculation F′(Z) = 2acZA−1/3 −4aa(A −2Z)/A = 0. Z∗= A 2 + [ac/(2aa)]A2/3 . (b) Interpretation and further calculation Z∗(100) = 42.96, N∗= 57.04, N∗/Z∗= 1.328 . F′′(Z) = 2acA−1/3 + 8aa/A > 0 . Physical check Coulomb repulsion shifts the minimum below Z=A/2. Integer Z, pairing, shell structure and neutron-proton mass difference refine the actual stability pattern.

Question 4

Competition between Coulomb and asymmetry energies favors neutron excess

At fixed A, ignore neutron-proton rest-mass difference and pairing. Approximate the Z-dependent mass energy by F(Z)=acZ2A−1/3+aa(A−2Z)2/AF(Z)=a_cZ^2A^{-1/3}+a_a(A-2Z)^2/A. Treat Z as continuous, with ac=.700MeVa_c=.700\,\mathrm{MeV} and aa=23.0MeVa_a=23.0\,\mathrm{MeV}.

Diagram shown in the original SVG worksheet.

  1. Minimize F to derive the preferred Z.

  2. Evaluate it for A=100 and infer the approximate neutron-to-proton ratio. Check that the stationary point is a minimum.

Question 4 - Solution

Competition between Coulomb and asymmetry energies favors neutron excess

Diagram shown in the original SVG worksheet.

(a) Method and calculation

F′(Z)=2acZA−1/3−4aa(A−2Z)/A=0.F\prime(Z)=2a_cZA^{-1/3}-4a_a(A-2Z)/A=0.Z*=A2+[ac/(2aa)]A2/3.\boxed{Z_* =\frac{A}{2+[a_c/(2a_a)]A^{2/3}}}.

(b) Interpretation and further calculation

Z*(100)=42.96,N*=57.04,N*/Z*=1.328.\boxed{Z_*(100)=42.96,\quad N_*=57.04,\quad N_*/Z_*=1.328}.F′′(Z)=2acA−1/3+8aa/A>0.\boxed{F\prime\prime(Z)=2a_cA^{-1/3}+8a_a/A>0}.

Physical check

Coulomb repulsion shifts the minimum below Z=A/2. Integer Z, pairing, shell structure and neutron-proton mass difference refine the actual stability pattern.