Nuclear Models — Question 3

Section 42-8 · Physics pages 7136–7137

Question 3 The mass formula combines competing contributions to binding Use the supplied model B = avA −asA2/3 −acZ(Z −1)A−1/3 −aa(A −2Z)2/A + δ. Coefficients are av = 15.5, as = 17.0, ac = .700, aa = 23.0 in MeV. For even-even nuclei take δ = 12/ √ A MeV. Consider A=64, Z=28. volume + pairing gains subtract surface + Coulomb + asymmetry penalties Schematic; labels, not drawing lengths, specify the data. (a) Evaluate the volume, surface, Coulomb, asymmetry and pairing terms. (b) Find total binding and binding per nucleon, and quantify how much the asymmetry term lowers B.
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Question 3 - Solution The mass formula combines competing contributions to binding volume + pairing gains subtract surface + Coulomb + asymmetry penalties (a) Method and calculation Bv = 992, Bs = −272, BC = −.700(28)(27)/4 = −132.3 MeV . Ba = −23(64 −56)2/64 = −23.0 MeV, δ = +1.50 MeV . (b) Interpretation and further calculation B = 992 −272 −132.3 −23.0 + 1.50 = 566.2 MeV . B/A = 8.8469 MeV, |Ba| = 23.0 MeV . Physical check The coefficients define an illustrative smooth model, not a precision empirical mass prediction. Shell corrections can produce deviations from its result.

Question 3

The mass formula combines competing contributions to binding

Use the supplied model B=avA−asA2/3−acZ(Z−1)A−1/3−aa(A−2Z)2/A+δB=a_vA-a_sA^{2/3}-a_cZ(Z-1)A^{-1/3}-a_a(A-2Z)^2/A+\delta. Coefficients are av=15.5a_v=15.5, as=17.0a_s=17.0, ac=.700a_c=.700, aa=23.0a_a=23.0 in MeV. For even-even nuclei take δ=12/A\delta=12/\sqrt A MeV. Consider A=64, Z=28.

Diagram shown in the original SVG worksheet.

  1. Evaluate the volume, surface, Coulomb, asymmetry and pairing terms.

  2. Find total binding and binding per nucleon, and quantify how much the asymmetry term lowers B.

Question 3 - Solution

The mass formula combines competing contributions to binding

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Bv=992,Bs=−272,BC=−.700(28)(27)/4=−132.3MeV.\boxed{B_v=992,\quad B_s=-272,\quad B_C=-.700(28)(27)/4=-132.3\,\mathrm{MeV}}.Ba=−23(64−56)2/64=−23.0MeV,δ=+1.50MeV.\boxed{B_a=-23(64-56)^2/64=-23.0\,\mathrm{MeV},\quad\delta=+1.50\,\mathrm{MeV}}.

(b) Interpretation and further calculation

B=992−272−132.3−23.0+1.50=566.2MeV.\boxed{B=992-272-132.3-23.0+1.50=566.2\,\mathrm{MeV}}.B/A=8.8469MeV,|Ba|=23.0MeV.\boxed{B/A=8.8469\,\mathrm{MeV},\quad|B_a|=23.0\,\mathrm{MeV}}.

Physical check

The coefficients define an illustrative smooth model, not a precision empirical mass prediction. Shell corrections can produce deviations from its result.