X Rays and the Ordering of the Elements — Question 10

Section 40-9 · Physics pages 6750–6751

Question 10 Adjacent elements become harder to separate by fractional K-line energy Assume E(Z) = C(Z −σ)2 with fixed C and σ. Compare neighboring atomic numbers Z and Z + 1. A spectrometer resolves two lines if their separation exceeds its full width δE. E I ∆E Schematic; labels, not drawing lengths, specify the data. (a) Derive the exact energy separation and fractional separation relative to E(Z). (b) For Z = 50, σ = 1, and E(Z) = 25.0 keV, find the separation and the minimum resolving power R = E(Z)/δE at equality.
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Question 10 - Solution Adjacent elements become harder to separate by fractional K-line energy E I ∆E (a) Method and calculation ∆E = C[(Z + 1 −σ)2 −(Z −σ)2] = C[2(Z −σ) + 1] . ∆E/E(Z) = 2/(Z −σ) + 1/(Z −σ)2 . (b) Interpretation and further calculation ∆E = 25.0(99/2401) = 1.0308 keV . δE = ∆E ⇒Rmin = 2401/99 = 24.25 . Physical check Absolute separation increases with Z in this model, while fractional separation decreases. Resolving power expresses a fractional-width requirement; a strict separation criterion requires a value just above the equality limit.

Question 10

Adjacent elements become harder to separate by fractional K-line energy

Assume E(Z)=C(Z−σ)2E(Z)=C(Z-\sigma)^2 with fixed C and σ\sigma. Compare neighboring atomic numbers Z and Z+1Z+1. A spectrometer resolves two lines if their separation exceeds its full width δE\delta E.

Diagram shown in the original SVG worksheet.

  1. Derive the exact energy separation and fractional separation relative to E(Z)E(Z).

  2. For Z=50Z=50, σ=1\sigma=1, and E(Z)=25.0keVE(Z)=25.0\,\mathrm{keV}, find the separation and the minimum resolving power ℛ=E(Z)/δE\mathcal R=E(Z)/\delta E at equality.

Question 10 - Solution

Adjacent elements become harder to separate by fractional K-line energy

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ΔE=C[(Z+1−σ)2−(Z−σ)2]=C[2(Z−σ)+1].\Delta E=C[(Z+1-\sigma)^2-(Z-\sigma)^2]=\boxed{C[2(Z-\sigma)+1]}.ΔE/E(Z)=2/(Z−σ)+1/(Z−σ)2.\boxed{\Delta E/E(Z)=2/(Z-\sigma)+1/(Z-\sigma)^2}.

(b) Interpretation and further calculation

ΔE=25.0(99/2401)=1.0308keV.\boxed{\Delta E=25.0(99/2401)=1.0308\,\mathrm{keV}}.δE=ΔE⇒ℛmin=2401/99=24.25.\delta E=\Delta E\Rightarrow\boxed{\mathcal R_{\min}=2401/99=24.25}.

Physical check

Absolute separation increases with Z in this model, while fractional separation decreases. Resolving power expresses a fractional-width requirement; a strict separation criterion requires a value just above the equality limit.