X Rays and the Ordering of the Elements — Question 9

Section 40-9 · Physics pages 6748–6749

Question 9 A nonradiative Auger channel partitions a core binding-energy difference Use a simplified independent-binding model with BK = 8.0 keV and BL = 1.0 keV. An L electron fills a K vacancy and transfers the released energy to a second L electron, ejecting it. Ignore rearrangement, recoil, and work-function effects. K L eA Schematic; labels, not drawing lengths, specify the data. (a) Find the Auger electron kinetic energy. (b) Compare with the Kα photon energy from a radiative alternative and account for the difference.
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Question 9 - Solution A nonradiative Auger channel partitions a core binding-energy difference K L eA (a) Method and calculation Efill = BK −BL = 8.0 −1.0 = 7.0 keV. KA = Efill −BL = BK −2BL = 6.0 keV . (b) Interpretation and further calculation EKα = BK −BL = 7.0 keV . EKα −KA = BL = 1.0 keV . Physical check The Auger channel leaves two outer vacancies instead of one. In real atoms the energies require configuration-dependent binding and relaxation corrections; this exercise states its simplified accounting model.

Question 9

A nonradiative Auger channel partitions a core binding-energy difference

Use a simplified independent-binding model with BK=8.0keVB_K=8.0\,\mathrm{keV} and BL=1.0keVB_L=1.0\,\mathrm{keV}. An L electron fills a K vacancy and transfers the released energy to a second L electron, ejecting it. Ignore rearrangement, recoil, and work-function effects.

Diagram shown in the original SVG worksheet.

  1. Find the Auger electron kinetic energy.

  2. Compare with the KαK_\alpha photon energy from a radiative alternative and account for the difference.

Question 9 - Solution

A nonradiative Auger channel partitions a core binding-energy difference

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Efill=BK−BL=8.0−1.0=7.0keV.E_{\mathrm{fill}}=B_K-B_L=8.0-1.0=7.0\,\mathrm{keV}.KA=Efill−BL=BK−2BL=6.0keV.K_A=E_{\mathrm{fill}}-B_L=B_K-2B_L=\boxed{6.0\,\mathrm{keV}}.

(b) Interpretation and further calculation

EKα=BK−BL=7.0keV.\boxed{E_{K\alpha}=B_K-B_L=7.0\,\mathrm{keV}}.EKα−KA=BL=1.0keV.\boxed{E_{K\alpha}-K_A=B_L=1.0\,\mathrm{keV}}.

Physical check

The Auger channel leaves two outer vacancies instead of one. In real atoms the energies require configuration-dependent binding and relaxation corrections; this exercise states its simplified accounting model.