Two- and Three-Dimensional Electron Traps — Question 9

Section 39-6 · Physics pages 6528–6529

Question 9 At fixed area the square minimizes the rectangular ground-state energy In a rectangular infinite well, Enxny = C(n2 x/L2 x + n2 y/L2 y), where C = π2ℏ2/(2m) and each index is a positive integer. Ignore spin. The area A = LxLy is fixed while the aspect ratio may vary. x y Lx Ly A = LxLy Schematic; labels, not drawing lengths, specify the data. (a) Find the geometry minimizing the ground energy and its minimum. (b) Compare the ground energy for Ly = 2Lx with this minimum.
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Question 9 - Solution At fixed area the square minimizes the rectangular ground-state energy x y Lx Ly A = LxLy (a) Method and calculation E11 = C ( 1 L2x + L2 x A2 ) ≥2C A . Lx = Ly = √ A, Emin = 2C/A . (b) Interpretation and further calculation Ly = 2Lx : L2 x = A/2 ⇒E11 = C(2 + 1/2)/A. E11/Emin = 5/4 . Physical check Concentrating confinement into one short direction costs more energy than the long direction saves. This comparison holds at fixed area, not fixed perimeter.

Question 9

At fixed area the square minimizes the rectangular ground-state energy

In a rectangular infinite well, Enxny=C(nx2/Lx2+ny2/Ly2)E_{n_xn_y}=C(n_x^2/L_x^2+n_y^2/L_y^2), where C=π2ℏ2/(2m)C=\pi^2\hbar^2/(2m) and each index is a positive integer. Ignore spin. The area 𝒜=LxLy\mathcal A=L_xL_y is fixed while the aspect ratio may vary.

Diagram shown in the original SVG worksheet.

  1. Find the geometry minimizing the ground energy and its minimum.

  2. Compare the ground energy for Ly=2LxL_y=2L_x with this minimum.

Question 9 - Solution

At fixed area the square minimizes the rectangular ground-state energy

Diagram shown in the original SVG worksheet.

(a) Method and calculation

E11=C(1Lx2+Lx2𝒜2)≥2C𝒜.E_{11}=C\left(\frac1{L_x^2}+\frac{L_x^2}{\mathcal A^2}\right)\ge\frac{2C}{\mathcal A}.Lx=Ly=𝒜,Emin=2C/𝒜.\boxed{L_x=L_y=\sqrt{\mathcal A},\qquad E_{\min}=2C/\mathcal A}.

(b) Interpretation and further calculation

Ly=2Lx:Lx2=𝒜/2⇒E11=C(2+1/2)/𝒜.L_y=2L_x:\quad L_x^2=\mathcal A/2\Rightarrow E_{11}=C(2+1/2)/\mathcal A.E11/Emin=5/4.\boxed{E_{11}/E_{\min}=5/4}.

Physical check

Concentrating confinement into one short direction costs more energy than the long direction saves. This comparison holds at fixed area, not fixed perimeter.