More Electron Traps — Question 8

Section 39-5 · Physics pages 6506–6507

Question 8 Tunneling between identical traps produces a level splitting and coherent transfer Two localized orthonormal states |L⟩, |R⟩are modeled by H = E0I −J(|L⟩⟨R| + |R⟩⟨L|), with J > 0. An electron starts in |L⟩. Use ℏ= 6.582 × 10−16 eV s and J = .00200 eV. L R J Schematic; labels, not drawing lengths, specify the data. (a) Find the two energy eigenstates and their splitting. (b) Derive the right-trap probability and find the first complete-transfer time.
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Question 8 - Solution Tunneling between identical traps produces a level splitting and coherent transfer L R J (a) Method and calculation |+⟩= (|L⟩+ |R⟩)/ √ 2, E+ = E0 −J; |−⟩= (|L⟩−|R⟩)/ √ 2, E−= E0 + J. ∆E = 2J = .00400 eV . (b) Interpretation and further calculation |Ψ(t)⟩= e−iE0t/ℏ[cos(Jt/ℏ)|L⟩+ i sin(Jt/ℏ)|R⟩], PR = sin2(Jt/ℏ) . ttransfer = πℏ/(2J) = 5.16949 × 10−13 s . Physical check Coherent transfer results from the relative phase of the split eigenstates. Environmental dephasing would require a different dynamical model.

Question 8

Tunneling between identical traps produces a level splitting and coherent transfer

Two localized orthonormal states |L⟩,|R⟩|L\rangle,|R\rangle are modeled by H=E0I−J(|L⟩⟨R|+|R⟩⟨L|)H=E_0I-J(|L\rangle\langle R|+|R\rangle\langle L|), with J>0J>0. An electron starts in |L⟩|L\rangle. Use ℏ=6.582×10−16eVs\hbar=6.582\times10^{-16}\,\mathrm{eV\,s} and J=.00200eVJ=.00200\,\mathrm{eV}.

Diagram shown in the original SVG worksheet.

  1. Find the two energy eigenstates and their splitting.

  2. Derive the right-trap probability and find the first complete-transfer time.

Question 8 - Solution

Tunneling between identical traps produces a level splitting and coherent transfer

Diagram shown in the original SVG worksheet.

(a) Method and calculation

|+⟩=(|L⟩+|R⟩)/2,E+=E0−J;|−⟩=(|L⟩−|R⟩)/2,E−=E0+J.|+\rangle=(|L\rangle+|R\rangle)/\sqrt2,\ E_+=E_0-J;\quad|-\rangle=(|L\rangle-|R\rangle)/\sqrt2,\ E_-=E_0+J.ΔE=2J=.00400eV.\boxed{\Delta E=2J=.00400\,\mathrm{eV}}.

(b) Interpretation and further calculation

|Ψ(t)⟩=e−iE0t/ℏ[cos⁡(Jt/ℏ)|L⟩+isin⁡(Jt/ℏ)|R⟩],PR=sin⁡2(Jt/ℏ).|\Psi(t)\rangle=e^{-iE_0t/\hbar}[\cos(Jt/\hbar)|L\rangle+i\sin(Jt/\hbar)|R\rangle],\quad\boxed{P_R=\sin^2(Jt/\hbar)}.ttransfer=πℏ/(2J)=5.16949×10−13s.\boxed{t_{\mathrm{transfer}}=\pi\hbar/(2J)=5.16949\times10^{-13}\,\mathrm s}.

Physical check

Coherent transfer results from the relative phase of the split eigenstates. Environmental dephasing would require a different dynamical model.