More Electron Traps — Question 7

Section 39-5 · Physics pages 6504–6505

Question 7 Size dispersion broadens a confinement line even without a short lifetime An ensemble of idealized nanostructures has transition energy ∆E = A/L2, where A is fixed. Widths have mean L0 and a narrow Gaussian spread σL = .0200L0. The central transition energy is .200 eV. Neglect lifetime and instrumental broadening. E wE ∆E0 Schematic; labels, not drawing lengths, specify the data. (a) Use linear propagation to find the energy standard deviation. (b) Find the approximate energy FWHM using wE = 2 √ 2 ln 2 σE.
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Question 7 - Solution Size dispersion broadens a confinement line even without a short lifetime E wE ∆E0 (a) Method and calculation d∆E dL = −2A L3 ⇒σE ∆E0 ≃2σL L0 . σE = .0400(.200) eV = .00800 eV . (b) Interpretation and further calculation wE = 2 √ 2 ln 2(.00800) eV = .0188386 eV . wE/∆E0 = .0941928 . Physical check This is inhomogeneous broadening from different structures, not a decay linewidth of one structure. The Gaussian approximation relies on the small fractional size spread.

Question 7

Size dispersion broadens a confinement line even without a short lifetime

An ensemble of idealized nanostructures has transition energy ΔE=A/L2\Delta E=A/L^2, where A is fixed. Widths have mean L0L_0 and a narrow Gaussian spread σL=.0200L0\sigma_L=.0200L_0. The central transition energy is .200eV.200\,\mathrm{eV}. Neglect lifetime and instrumental broadening.

Diagram shown in the original SVG worksheet.

  1. Use linear propagation to find the energy standard deviation.

  2. Find the approximate energy FWHM using wE=22ln⁡2σEw_E=2\sqrt{2\ln2}\,\sigma_E.

Question 7 - Solution

Size dispersion broadens a confinement line even without a short lifetime

Diagram shown in the original SVG worksheet.

(a) Method and calculation

dΔEdL=−2AL3⇒σEΔE0≃2σLL0.\frac{d\Delta E}{dL}=-\frac{2A}{L^3}\Rightarrow\frac{\sigma_E}{\Delta E_0}\simeq\frac{2\sigma_L}{L_0}.σE=.0400(.200)eV=.00800eV.\boxed{\sigma_E=.0400(.200)\,\mathrm{eV}=.00800\,\mathrm{eV}}.

(b) Interpretation and further calculation

wE=22ln⁡2(.00800)eV=.0188386eV.\boxed{w_E=2\sqrt{2\ln2}(.00800)\,\mathrm{eV}=.0188386\,\mathrm{eV}}.wE/ΔE0=.0941928.\boxed{w_E/\Delta E_0=.0941928}.

Physical check

This is inhomogeneous broadening from different structures, not a decay linewidth of one structure. The Gaussian approximation relies on the small fractional size spread.