Energies of a Trapped Electron — Question 3

Section 39-2 · Physics pages 6436–6437

Question 3 A radiative cascade conserves total photon energy but not photon wavelength sums An electron starts at n = 4 in a 1.00 nm infinite well and ends at n = 1. Compare a direct transition with the cascade 4 →3 →2 →1, assuming the transitions occur and recoil is negligible. Model the electron by a one-dimensional infinite well: En = Cn2/L2, n = 1, 2, . . ., with C = .376 eV nm2 when L is in nanometers. Set the interior potential to zero. n = 1 n = 2 n = 3 n = 4 E Schematic; labels, not drawing lengths, specify the data. (a) Find the three cascade photon energies and their sum. (b) Compare the mean cascade photon energy with the single direct photon energy.
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Question 3 - Solution A radiative cascade conserves total photon energy but not photon wavelength sums n = 1 n = 2 n = 3 n = 4 E (a) Method and calculation (E43, E32, E21) = E1(16 −9, 9 −4, 4 −1) = E1(7, 5, 3). (E43, E32, E21) = (2.632, 1.880, 1.128) eV . (b) Interpretation and further calculation Etotal = 15E1 = 5.640 eV = E41 . Ecascade = E41/3 = 1.880 eV . Physical check Energy differences telescope along the cascade. Wavelengths are inversely proportional to photon energies, so wavelength sums do not obey this conservation rule.

Question 3

A radiative cascade conserves total photon energy but not photon wavelength sums

An electron starts at n=4n=4 in a 1.00nm1.00\,\mathrm{nm} infinite well and ends at n=1n=1. Compare a direct transition with the cascade 4→3→2→14\to3\to2\to1, assuming the transitions occur and recoil is negligible. Model the electron by a one-dimensional infinite well: En=Cn2/L2E_n=Cn^2/L^2, n=1,2,…n=1,2,\ldots, with C=.376eVnm2C=.376\,\mathrm{eV\,nm^2} when L is in nanometers. Set the interior potential to zero.

Diagram shown in the original SVG worksheet.

  1. Find the three cascade photon energies and their sum.

  2. Compare the mean cascade photon energy with the single direct photon energy.

Question 3 - Solution

A radiative cascade conserves total photon energy but not photon wavelength sums

Diagram shown in the original SVG worksheet.

(a) Method and calculation

(E43,E32,E21)=E1(16−9,9−4,4−1)=E1(7,5,3).(E_{43},E_{32},E_{21})=E_1(16-9,9-4,4-1)=E_1(7,5,3).(E43,E32,E21)=(2.632,1.880,1.128)eV.\boxed{(E_{43},E_{32},E_{21})=(2.632,1.880,1.128)\,\mathrm{eV}}.

(b) Interpretation and further calculation

Etotal=15E1=5.640eV=E41.\boxed{E_{\mathrm{total}}=15E_1=5.640\,\mathrm{eV}=E_{41}}.E¯cascade=E41/3=1.880eV.\boxed{\overline E_{\mathrm{cascade}}=E_{41}/3=1.880\,\mathrm{eV}}.

Physical check

Energy differences telescope along the cascade. Wavelengths are inversely proportional to photon energies, so wavelength sums do not obey this conservation rule.