Energies of a Trapped Electron — Question 2

Section 39-2 · Physics pages 6434–6435

Question 2 Two adjacent spectral gaps identify both the level index and well width Consecutive adjacent-level gaps in an infinite electron well are En+1 −En = 1.00 eV and En+2 −En+1 = 1.40 eV. Model the electron by a one-dimensional infinite well: En = Cn2/L2, n = 1, 2, . . ., with C = .376 eV nm2 when L is in nanometers. Set the interior potential to zero. n = n n = n + 1 n = n + 2 E Schematic; labels, not drawing lengths, specify the data. (a) Infer n from the ratio of the gaps. (b) Find the ground energy and well width.
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Question 2 - Solution Two adjacent spectral gaps identify both the level index and well width n = n n = n + 1 n = n + 2 E (a) Method and calculation 1.40 1.00 = 2n + 3 2n + 1 ⇒2.8n + 1.4 = 2n + 3. n = 2 . (b) Interpretation and further calculation E1 = 1.00/(2n + 1) = .200 eV . L = √ C/E1 = √ 1.88 nm = 1.37113 nm . Physical check The ratio isolates the integer index independently of width. A ratio inconsistent with an integer would challenge the assumed box model or line assignment.

Question 2

Two adjacent spectral gaps identify both the level index and well width

Consecutive adjacent-level gaps in an infinite electron well are En+1−En=1.00eVE_{n+1}-E_n=1.00\,\mathrm{eV} and En+2−En+1=1.40eVE_{n+2}-E_{n+1}=1.40\,\mathrm{eV}. Model the electron by a one-dimensional infinite well: En=Cn2/L2E_n=Cn^2/L^2, n=1,2,…n=1,2,\ldots, with C=.376eVnm2C=.376\,\mathrm{eV\,nm^2} when L is in nanometers. Set the interior potential to zero.

Diagram shown in the original SVG worksheet.

  1. Infer n from the ratio of the gaps.

  2. Find the ground energy and well width.

Question 2 - Solution

Two adjacent spectral gaps identify both the level index and well width

Diagram shown in the original SVG worksheet.

(a) Method and calculation

1.401.00=2n+32n+1⇒2.8n+1.4=2n+3.\frac{1.40}{1.00}=\frac{2n+3}{2n+1}\Rightarrow 2.8n+1.4=2n+3.n=2.\boxed{n=2}.

(b) Interpretation and further calculation

E1=1.00/(2n+1)=.200eV.\boxed{E_1=1.00/(2n+1)=.200\,\mathrm{eV}}.L=C/E1=1.88nm=1.37113nm.\boxed{L=\sqrt{C/E_1}=\sqrt{1.88}\,\mathrm{nm}=1.37113\,\mathrm{nm}}.

Physical check

The ratio isolates the integer index independently of width. A ratio inconsistent with an integer would challenge the assumed box model or line assignment.