The Photoelectric Effect — Question 10

Section 38-2 · Physics pages 6290–6291

Question 10 A specified multiphoton channel changes the intensity scaling and threshold An intense source supplies 2.00 eV photons to a surface with work function 4.50 eV. Assume an allowed n-photon channel transfers nhf to one electron, with emission rate proportional to In in the weak, unsaturated limit for that channel. e− 3hf Schematic; labels, not drawing lengths, specify the data. (a) Find the smallest allowed n and its maximum electron kinetic energy. (b) Find the predicted rate multiplier when intensity doubles and explain why this is outside the single-photon model.
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Question 10 - Solution A specified multiphoton channel changes the intensity scaling and threshold e− 3hf (a) Method and calculation nhf ≥ϕ ⇒ n ≥4.50/2.00 = 2.25. nmin = 3 , Kmax = 6.00 −4.50 = 1.50 eV . (b) Interpretation and further calculation R ∝I3 ⇒ R(2I)/R(I) = 8 . hf = 2.00 eV < ϕ ⇒ the one-photon channel remains closed. Physical check The intensity power law is a supplied perturbative model; at saturation or with competing channels it need not hold.

Question 10

A specified multiphoton channel changes the intensity scaling and threshold

An intense source supplies 2.00 eV photons to a surface with work function 4.50 eV. Assume an allowed n-photon channel transfers nhfnhf to one electron, with emission rate proportional to ℐn\mathcal I^n in the weak, unsaturated limit for that channel.

Diagram shown in the original SVG worksheet.

  1. Find the smallest allowed n and its maximum electron kinetic energy.

  2. Find the predicted rate multiplier when intensity doubles and explain why this is outside the single-photon model.

Question 10 - Solution

A specified multiphoton channel changes the intensity scaling and threshold

Diagram shown in the original SVG worksheet.

(a) Method and calculation

nhf≥ϕ⇒n≥4.50/2.00=2.25.nhf\ge\phi\quad\Rightarrow\quad n\ge4.50/2.00=2.25.nmin=3,Kmax=6.00−4.50=1.50eV.\boxed{n_{\min}=3},\qquad\boxed{K_{\max}=6.00-4.50=1.50\,\mathrm{eV}}.

(b) Interpretation and further calculation

R∝ℐ3⇒R(2ℐ)/R(ℐ)=8.R\propto\mathcal I^3\quad\Rightarrow\quad\boxed{R(2\mathcal I)/R(\mathcal I)=8}.hf=2.00eV<ϕ⇒the one-photon channel remains closed.hf=2.00\,\mathrm{eV}<\phi\quad\Rightarrow\quad\text{the one-photon channel remains closed}.

Physical check

The intensity power law is a supplied perturbative model; at saturation or with competing channels it need not hold.