The Photoelectric Effect — Question 9

Section 38-2 · Physics pages 6288–6289

Question 9 A classical accumulation estimate predicts a long delay under a stated microscopic model A hypothetical classical model assigns one electron an effective collecting area a = 10−20 m2 under intensity I = 10−3 W/m2. It must accumulate work function energy ϕ = 2.00 eV before emission. Take 1 eV = 1.60 × 10−19 J. t Eaccumulated ϕ Schematic; labels, not drawing lengths, specify the data. (a) Calculate the accumulation time predicted by this model. (b) Contrast its inverse-intensity dependence with one-photon energy transfer when hf > ϕ.
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Question 9 - Solution A classical accumulation estimate predicts a long delay under a stated microscopic model t Eaccumulated ϕ (a) Method and calculation Pe = Ia = 10−23 W, ϕ = 3.20 × 10−19 J. tacc = ϕ/(Ia) = 3.20 × 104 s . (b) Interpretation and further calculation tacc ∝I−1. One absorption: hf ≥ϕ, Kmax = hf −ϕ. Physical check Photon absorption does not require gradual accumulation from many weak cycles. This does not imply every microscopic response or photon waiting time is literally zero.

Question 9

A classical accumulation estimate predicts a long delay under a stated microscopic model

A hypothetical classical model assigns one electron an effective collecting area a=10−20m2a=10^{-20}\,\mathrm m^2 under intensity ℐ=10−3W/m2\mathcal I=10^{-3}\,\mathrm{W/m^2}. It must accumulate work function energy ϕ=2.00eV\phi=2.00\,\mathrm{eV} before emission. Take 1eV=1.60×10−19J1\,\mathrm{eV}=1.60\times10^{-19}\,\mathrm J.

Diagram shown in the original SVG worksheet.

  1. Calculate the accumulation time predicted by this model.

  2. Contrast its inverse-intensity dependence with one-photon energy transfer when hf>ϕhf>\phi.

Question 9 - Solution

A classical accumulation estimate predicts a long delay under a stated microscopic model

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Pe=ℐa=10−23W,ϕ=3.20×10−19J.P_e=\mathcal I a=10^{-23}\,\mathrm W,\qquad\phi=3.20\times10^{-19}\,\mathrm J.tacc=ϕ/(ℐa)=3.20×104s.\boxed{t_{\mathrm{acc}}=\phi/(\mathcal I a)=3.20\times10^4\,\mathrm s}.

(b) Interpretation and further calculation

tacc∝ℐ−1.t_{\mathrm{acc}}\propto\mathcal I^{-1}.One absorption:hf≥ϕ,Kmax=hf−ϕ.\text{One absorption:}\quad hf\ge\phi,\qquad K_{\max}=hf-\phi.

Physical check

Photon absorption does not require gradual accumulation from many weak cycles. This does not imply every microscopic response or photon waiting time is literally zero.