The Photon, the Quantum of Light — Question 8

Section 38-1 · Physics pages 6266–6267

Question 8 A photon-budget limit sets the range of an isotropic optical beacon A monochromatic isotropic source has photon luminosity ˙Ns = 1018 s−1. A small receiver of collecting area A = .0100 m2 has efficiency η = .200 and faces the source. Neglect absorption and background. r A Schematic; labels, not drawing lengths, specify the data. (a) Find the detected count rate at range r. (b) Find the maximum range for a mean rate of at least one detected photon per second.
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Question 8 - Solution A photon-budget limit sets the range of an isotropic optical beacon r A (a) Method and calculation ΦN(r) = ˙Ns/(4πr2), R = ηAΦN. R = ηA ˙Ns 4πr2 . (b) Interpretation and further calculation R ≥Rmin ⇒ r ≤ √ ηA ˙Ns 4πRmin . rmax = 1.26157 × 107 m (Rmin = 1 s−1) . Physical check A mean count of one per second does not guarantee a count in every second; counting fluctuations remain.

Question 8

A photon-budget limit sets the range of an isotropic optical beacon

A monochromatic isotropic source has photon luminosity Ṅs=1018s−1\dot N_s=10^{18}\,\mathrm{s^{-1}}. A small receiver of collecting area A=.0100m2A=.0100\,\mathrm m^2 has efficiency η=.200\eta=.200 and faces the source. Neglect absorption and background.

Diagram shown in the original SVG worksheet.

  1. Find the detected count rate at range r.

  2. Find the maximum range for a mean rate of at least one detected photon per second.

Question 8 - Solution

A photon-budget limit sets the range of an isotropic optical beacon

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ΦN(r)=Ṅs/(4πr2),R=ηAΦN.\Phi_N(r)=\dot N_s/(4\pi r^2),\quad R=\eta A\Phi_N.R=ηAṄs4πr2.\boxed{R=\frac{\eta A\dot N_s}{4\pi r^2}}.

(b) Interpretation and further calculation

R≥Rmin⇒r≤ηAṄs4πRmin.R\ge R_{\min}\quad\Rightarrow\quad r\le\sqrt{\frac{\eta A\dot N_s}{4\pi R_{\min}}}.rmax=1.26157×107m(Rmin=1s−1).\boxed{r_{\max}=1.26157\times10^7\,\mathrm m\quad(R_{\min}=1\,\mathrm{s^{-1}})}.

Physical check

A mean count of one per second does not guarantee a count in every second; counting fluctuations remain.