The Photon, the Quantum of Light — Question 7

Section 38-1 · Physics pages 6264–6265

Question 7 An ideal two-level absorber selects an energy difference rather than a lower bound An ideal isolated two-level system has level separation ∆E = 2.00 eV. Assume negligible recoil and linewidth, and no other levels, ionization or multiphoton channels. Use hc = 1240 eV nm and 1 eV = 1.60 × 10−19 J. ∆E Schematic; labels, not drawing lengths, specify the data. (a) Find the resonant one-photon wavelength. (b) Decide whether a 310 nm photon can drive this transition and quantify its energy mismatch.
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Question 7 - Solution An ideal two-level absorber selects an energy difference rather than a lower bound ∆E (a) Method and calculation Eγ = ∆E ⇒ λres = hc/∆E = 620 nm . E310 = 1240/310 = 4.00 eV. (b) Interpretation and further calculation E310 −∆E = 2.00 eV̸ = 0 . No allowed one-photon absorption into the specified upper level . Physical check A discrete transition requires energy matching under these assumptions. Having more photon energy is not by itself sufficient.

Question 7

An ideal two-level absorber selects an energy difference rather than a lower bound

An ideal isolated two-level system has level separation ΔE=2.00eV\Delta E=2.00\,\mathrm{eV}. Assume negligible recoil and linewidth, and no other levels, ionization or multiphoton channels. Use hc=1240eVnmhc=1240\,\mathrm{eV\,nm} and 1eV=1.60×10−19J1\,\mathrm{eV}=1.60\times10^{-19}\,\mathrm J.

Diagram shown in the original SVG worksheet.

  1. Find the resonant one-photon wavelength.

  2. Decide whether a 310 nm photon can drive this transition and quantify its energy mismatch.

Question 7 - Solution

An ideal two-level absorber selects an energy difference rather than a lower bound

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Eγ=ΔE⇒λres=hc/ΔE=620nm.E_\gamma=\Delta E\quad\Rightarrow\quad\boxed{\lambda_{\mathrm{res}}=hc/\Delta E=620\,\mathrm{nm}}.E310=1240/310=4.00eV.E_{310}=1240/310=4.00\,\mathrm{eV}.

(b) Interpretation and further calculation

E310−ΔE=2.00eV≠0.\boxed{E_{310}-\Delta E=2.00\,\mathrm{eV}\ne0}.No allowed one-photon absorption into the specified upper level.\boxed{\text{No allowed one-photon absorption into the specified upper level}}.

Physical check

A discrete transition requires energy matching under these assumptions. Having more photon energy is not by itself sufficient.