Gratings: Dispersion and Resolving Power — Question 9

Section 36-8 · Physics pages 6008–6009

Question 9 Angular pointing noise creates a wavelength-calibration floor A first-order grating has d = 2.00 µm and measures λ = 600 nm at normal incidence. The observed diffraction angle has standard uncertainty σθ = 10.0 µrad. Treat d and incidence angle as exact. d N illuminated slits angle uncertainty σθ Schematic; labels, not drawing lengths, specify the data. (a) Propagate the angular uncertainty into wavelength uncertainty. (b) Find the illuminated slit count at which the ideal Rayleigh separation becomes equal in magnitude to this uncertainty scale.
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Question 9 - Solution Angular pointing noise creates a wavelength-calibration floor d N illuminated slits angle uncertainty σθ (a) Method and calculation λ = d sin θ =⇒σλ = d| cos θ|σθ . sin θ = 0.300 =⇒σλ = 0.0190788 nm . (b) Interpretation and further calculation λ/N∗= σλ =⇒N∗= λ/σλ. N∗= 31448.5 ≃3.14 × 104 . Physical check The comparison is between two different width conventions, used here only as a scale estimate; adding grooves alone does not reduce pointing noise.

Question 9

Angular pointing noise creates a wavelength-calibration floor

A first-order grating has d=2.00μmd=2.00\,\mu\mathrm m and measures λ=600nm\lambda=600\,\mathrm{nm} at normal incidence. The observed diffraction angle has standard uncertainty σθ=10.0μrad\sigma_\theta=10.0\,\mu\mathrm{rad}. Treat d and incidence angle as exact.

Diagram shown in the original SVG worksheet.

  1. Propagate the angular uncertainty into wavelength uncertainty.

  2. Find the illuminated slit count at which the ideal Rayleigh separation becomes equal in magnitude to this uncertainty scale.

Question 9 - Solution

Angular pointing noise creates a wavelength-calibration floor

Diagram shown in the original SVG worksheet.

(a) Method and calculation

λ=dsin⁡θ⇒σλ=d|cos⁡θ|σθ.\lambda=d\sin\theta\Longrightarrow\boxed{\sigma_\lambda=d|\cos\theta|\sigma_\theta}.sin⁡θ=0.300⇒σλ=0.0190788nm.\sin\theta=0.300\Longrightarrow\boxed{\sigma_\lambda=0.0190788\,\mathrm{nm}}.

(b) Interpretation and further calculation

λ/N*=σλ⇒N*=λ/σλ.\lambda/N_*=\sigma_\lambda\Longrightarrow N_*=\lambda/\sigma_\lambda.N*=31448.5≃3.14×104.\boxed{N_*=31448.5\simeq3.14\times10^4}.

Physical check

The comparison is between two different width conventions, used here only as a scale estimate; adding grooves alone does not reduce pointing noise.