Diffraction Gratings — Question 8

Section 36-7 · Physics pages 5986–5987

Question 8 The Littrow condition selects a blaze wavelength for a reflection grating For a reflection grating used in Littrow geometry, the incident and diffracted beams retrace at angle θB from the grating normal, and 2d sin θB = mλB. Assume groove facets are oriented so this direction is their specular blaze direction. The groove density is 600 per millimeter. θB Schematic; labels, not drawing lengths, specify the data. (a) Find the blaze angle for λB = 500 nm in order m=2. (b) At the same geometry, find the blaze wavelength in first order and explain what the blaze condition does not determine.
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Question 8 - Solution The Littrow condition selects a blaze wavelength for a reflection grating θB (a) Method and calculation d = 1.66667 µm, sin θB = 2(500 nm) 2d = 0.300. θB = 17.4576◦. (b) Interpretation and further calculation mλB = 2d sin θB = 1000 nm =⇒λB,m=1 = 1000 nm . The angular condition alone does not specify absolute diffraction efficiency. Physical check Blazing aligns a preferred groove reflection direction with a grating order; efficiency still depends on material, polarization, and groove details.

Question 8

The Littrow condition selects a blaze wavelength for a reflection grating

For a reflection grating used in Littrow geometry, the incident and diffracted beams retrace at angle θB\theta_B from the grating normal, and 2dsin⁡θB=mλB2d\sin\theta_B=m\lambda_B. Assume groove facets are oriented so this direction is their specular blaze direction. The groove density is 600 per millimeter.

Diagram shown in the original SVG worksheet.

  1. Find the blaze angle for λB=500nm\lambda_B=500\,\mathrm{nm} in order m=2.

  2. At the same geometry, find the blaze wavelength in first order and explain what the blaze condition does not determine.

Question 8 - Solution

The Littrow condition selects a blaze wavelength for a reflection grating

Diagram shown in the original SVG worksheet.

(a) Method and calculation

d=1.66667μm,sin⁡θB=2(500nm)2d=0.300.d=1.66667\,\mu\mathrm m,\quad\sin\theta_B=\frac{2(500\,\mathrm{nm})}{2d}=0.300.θB=17.4576∘.\boxed{\theta_B=17.4576^\circ}.

(b) Interpretation and further calculation

mλB=2dsin⁡θB=1000nm⇒λB,m=1=1000nm.m\lambda_B=2d\sin\theta_B=1000\,\mathrm{nm}\Longrightarrow\boxed{\lambda_{B,m=1}=1000\,\mathrm{nm}}.The angular condition alone does not specify absolute diffraction efficiency.\boxed{\text{The angular condition alone does not specify absolute diffraction efficiency.}}

Physical check

Blazing aligns a preferred groove reflection direction with a grating order; efficiency still depends on material, polarization, and groove details.